导出数据表单xls表单多个表单post]

Question

 <?php foreach($renewals as $row) { ?>
            <tr >
                <td style="width:50%;"><?php echo $row['renew_year']; ?></td>
                <td style="width:40%;"><?php echo $row['total']; ?></td>

                <td><a href="<?php $options['id'] = 18; echo $this->url("admin",$options); ?>?renew_year=<?php echo $row['renew_year']?>">View</a>

                </td>
                <td>
                    <input type="button" name="exportXLSRvt" id="exportXLSRvt" class="button exportIcon" title="Export XLS">
                <form id="frmExportRvt" name="frmExport" method="post"
                      action="<?php echo $this->url("admin", array("controller" => "members", "action" => "indexExport", "id" => 18)); ?>?renew_year=<?php echo $row['renew_year'] ?>"
                      style="display: none;">
                    <input type="hidden" name="hdn_export_type" id="hdn_export_type" value="xls"/>
                </form>
                </td>
            </tr>
            <?php } ?>

以上代码是导出数据到xls我已经创建了多个表单.....取决于数据，但我们曾经点击过图像，它发布了相同的数据，所以如果有人有替代的解决方案，请帮助我]

Answer 1

如果，无论你点击什么图像，你总是得到相同的数据，这仅仅意味着你在每个表单下都有相同的动作。

所以我将重点放在这一行上

 action="<?php echo $this->url("admin", array("controller" => "members", 
 "action" => "indexExport", "id" => 18)); ?>
 ?renew_year=<?php echo $row['renew_year'] ?>"

也许你必须转换成这样的东西：

 action="<?php echo $this->url("admin", array("controller" => "members", 
 "action" => "indexExport", "id" => 18, "renew_year" => $row['renew_year'])); ?>"

你应该能够从你的控制器调用$_GET‘’renew_year‘并加载正确的数据。