原始字符串的特殊字符- Objective C

Question

我已尝试将字符串(包含特殊字符)转换为原始字符串。从服务接收的字符串。我试过很多代码。但是我不能得到原始的字符串。

我尝试了以下代码

// \U00e0\U00ae\U0089\U00e0\U00ae\U00b2\U00e0\U00ae\U0095\U00e0\U00ae\U00ae\U00e0\U00af\U008d

NSString *name2escaped = @"\\U00e0\\U00ae\\U0089\\U00e0\\U00ae\\U00b2\\U00e0\\U00ae\\U0095\\U00e0\\U00ae\\U00ae\\U00e0\\U00af\\U008d";
NSString *name2 = [NSString stringWithCString:[name2escaped cStringUsingEncoding:NSUTF8StringEncoding] encoding:NSNonLossyASCIIStringEncoding];
NSLog(@"name2 = %@", name2);
inputvalue.stringValue = name2;
NSLog (@"%@",name2);

输出打印:à®à®²à®à

我在Mac开发10.9Mavericks Service，有时也会发送中文字符。有人能帮我吗？

Answer 1

根据您的要求，output应为Tamil or Chinese or English Language

将NSNonLossyASCIIStringEncoding更改为NSUTF16StringEncoding：

NSString *name2escaped = @"\\U00e0\\U00ae\\U0089\\U00e0\\U00ae\\U00b2\\U00e0\\U00ae\\U0095\\U00e0\\U00ae\\U00ae\\U00e0\\U00af\\U008d";
NSString *name2 = [NSString stringWithCString:[name2escaped cStringUsingEncoding:NSUTF8StringEncoding] encoding:NSUTF16StringEncoding];
NSLog(@"name2 = %@", name2);

输出为: name2 =屵〰攰屵〰慥屵〰㠹屵〰攰屵〰慥屵〰戲屵〰攰屵〰慥屵〰㤵屵〰攰屵〰慥屵〰慥屵〰攰屵〰慦屵〰㡤-

Answer 2

我做到了我的代码是

- (NSString *) OrigninalString:(NSString *)getfilername
{
const char *c;
NSString *name2escaped = [NSString stringWithFormat:@"%@",getfilername];
NSString *string = [NSString
                    stringWithCString:[name2escaped cStringUsingEncoding:NSUTF8StringEncoding]
                    encoding:NSNonLossyASCIIStringEncoding];
c = [string cStringUsingEncoding:NSISOLatin1StringEncoding];
if (!c) {
    c = [name2escaped cStringUsingEncoding:NSISOLatin1StringEncoding];
}
NSString *newString = [NSString stringWithCString:c encoding:NSUTF8StringEncoding];
c = nil;
string = nil;
return newString;
}