主类:
public class Card
{
private String cardShort;
private String cardClas;
private String cardType;
public Card(String cardClas, String cardType)
{
this.cardType = cardType;
this.cardClas = cardClas;
}
public void cardSelector()
{
switch(cardClas.toUpperCase())
{
case "J" : cardClas = "Jack";
break;
case "K" : cardClas = "King";
break;
case "Q" : cardClas = "Queen";
break;
case "A" : cardClas = "Ace";
break;
case "2" : cardClas = "Two";
break;
case "3" : cardClas = "Three";
break;
case "4" : cardClas = "Four";
break;
case "5" : cardClas = "Five";
break;
case "6" : cardClas = "Six";
break;
case "7" : cardClas = "Seven";
break;
case "8" : cardClas = "Eight";
break;
case "9" : cardClas = "Nine";
break;
case "10" : cardClas = "Ten";
break;
}
switch(cardType.toUpperCase())
{
case "S" : cardClas = "Spades";
break;
case "C" : cardClas = "Clubs";
break;
case "H" : cardClas = "Hearts";
break;
case "D" : cardClas = "Diamonds";
break;
}
}
public String getClasses()
{
return cardType;
}
public String getType()
{
return cardClas;
}
public String toString()
{
String theory = getClasses() + " of " + getType();
return theory;
}}
测试仪:
import java.util.Scanner;
public class CardTester
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.println("Enter card: ");
String shortHand = sc.next();
if(shortHand.length() == 2)
{
Card c = new Card(shortHand.substring(0,1),shortHand.substring(1,2) );
c.cardSelector();
System.out.println(c.toString());
} else if(shortHand.length() == 3)
{
Card c = new Card(shortHand.substring(0,2), shortHand.substring(2,3));
c.cardSelector();
System.out.println(c.toString());
}
}}
控制台:"Enter card: AS S of Spades“应该输出"Ace of Spades”。尝试了一堆不同的修复,不确定是什么导致了现在的问题。
第一次使用开关箱,可能需要一些帮助…谢谢!
发布于 2014-10-27 08:05:14
您的两个switch语句都在设置cardClas。您需要其中之一来设置cardType。
另外,你的两个getter非常容易混淆。您似乎以某种方式交换了名称;因此您有返回cardType的getClasses和返回cardClas的getType。你可能想解决这个问题。
发布于 2014-10-27 08:06:48
首先,我希望您使用的是Java7,如果不是这样(或者您只是想简化它),那么您可以在switch语句中使用char而不是String。同时,在两个switch语句中都设置了cardClas。此外,getClasses方法返回cardType,getCardType返回cardClas
https://stackoverflow.com/questions/26579411
复制相似问题