使用整数列表时，不支持-的操作数类型：'str‘和'int’

Question

def run_counter(card_list, num_cards):
    hand = functions1.hand_sample(card_list, num_cards)
    hand1 = functions1.hand_shuffle(card_list, num_cards)
    srt_hand = sorted(hand)
    srt_hand1 = sorted(hand1)
    prop_hand = functions1.proper_hand(srt_hand)
    prop_hand1 = functions1.proper_hand(srt_hand1)
    run1 = 0
    i = 0
    for count in range(len(srt_hand)-1):
        if srt_hand[i] == srt_hand[i+1] - 1:
            run1 += 1
    run2 = 0
    i = 0
    for count in range(len(srt_hand1)-1):
        if srt_hand1[i] == srt_hand1[i+1] - 1:
            run2 += 1
    return run1+1, run2+1, prop_hand, prop_hand1

我有自己生成的一手牌，并存储在排序列表'srt_hand‘和'srt_hand1’中。我做了一个函数来计算手中游程的长度。我去测试它，但它总是说'if srt_handi == srt_handi+1 - 1:‘是一个不支持的操作数类型。为什么会这样呢？这没有任何意义，因为我索引的是一个整数列表...

我以前用过同样的排序技术，它起作用了(除了它在第一次运行后停止)：

run1 = 0
i = 0
while i < len(srt_hand)-1 and run1 < 2:
    while i < len(srt_hand)-1 and srt_hand[i] == srt_hand[i+1] - 1:
        if srt_hand[i] == srt_hand[i+1]:
            i += 1
        run1 += 1
        i += 1
    i += 1
run2 = 0
i = 0
while i < len(srt_hand1)-1 and run2 < 2:
    while i < len(srt_hand1)-1 and srt_hand1[i] == srt_hand1[i+1] - 1:
        if srt_hand[i] == srt_hand[i+1]:
            i += 1
        run2 += 1
        i += 1
    i += 1
return run1+1, run2+1, prop_hand, prop_hand1

Answer 1

在python3.3中，sorted函数返回一个生成器，因此您不能像在srt_hand[i]中那样对它进行索引(这将引发异常)。