首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >Python Sentinel不工作

Python Sentinel不工作
EN

Stack Overflow用户
提问于 2014-03-14 23:34:10
回答 2查看 130关注 0票数 0

我不明白为什么这个前哨不能工作。我找遍了所有地方都找不到答案。谢谢你的帮助!

代码语言:javascript
复制
gas = 0
miles = 0
miles = int(input("Enter number of miles driven(enter -11 to exit): "))
while miles != -11:
    gas = int(input("Enter the number of gallons of gas used: "))
    print ("The number of miles entered was:", miles)
    print ("The number of gallons of gas used was:", gas)
    mpg = miles/gas
    print ("The MPG was:", mpg)

这就是结果:

代码语言:javascript
复制
Enter number of miles driven(enter -11 to exit): 100
Enter the number of gallons of gas used: 10
The number of miles entered was: 100
The number of gallons of gas used was: 10
The MPG was: 10.0
Enter the number of gallons of gas used: -11
The number of miles entered was: 100
The number of gallons of gas used was: -11
The MPG was: -9.090909090909092
Enter the number of gallons of gas used:
EN

回答 2

Stack Overflow用户

发布于 2014-03-14 23:44:14

您还应该包括循环中的里程数。

代码语言:javascript
复制
gas = 0
miles = 0
while miles != -11:
    miles = int(input("Enter number of miles driven(enter -11 to exit): "))
    gas = int(input("Enter the number of gallons of gas used: "))
    print ("The number of miles entered was:", miles)
    print ("The number of gallons of gas used was:", gas)
    mpg = miles/gas
    print ("The MPG was:", mpg)

即使在这种情况下,程序在检查前哨条件之前也会询问气体量,因此更好的版本应该是:

代码语言:javascript
复制
gas = 0
miles = 0
while True:
    miles = int(input("Enter number of miles driven(enter -11 to exit): "))
    if miles==-11:
        break
    gas = int(input("Enter the number of gallons of gas used: "))
    print ("The number of miles entered was:", miles)
    print ("The number of gallons of gas used was:", gas)
    mpg = miles/gas
    print ("The MPG was:", mpg)
票数 1
EN

Stack Overflow用户

发布于 2014-03-14 23:45:56

用一个空行代替“前哨”...我也会使用iter的两个表单版本重写它,如下所示:

代码语言:javascript
复制
for miles in iter(lambda: input('Enter miles (or enter to exit): '), ''):
    try:
        miles = int(miles)
        gas = int(input('Enter gas used: '))
        print('MPG was: ', miles/gas)
    except (ValueError, ZeroDivisionError): # int type conversion failed or div by 0
        print('You must enter valid numbers and gas used must be > 0 or press enter to exit')
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/22409432

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档