错误:无法将'record*‘转换为'record**’

Question

我不明白为什么当我编译我的代码时会出现这个错误。我相信我做的每件事都和以前一样，但这一次不起作用。

stack.cpp:30: error: cannot convert 'record*' to 'record**' for argument '2' to 'void filename(char*, record**)'

在编译时会有更多的错误，但我会把它们找出来。(我还必须手动添加每行表示“代码”的4个空格，所以如果其他人可以告诉我如何自动完成此操作！那太好了!

#include <iostream>
#include <cstdlib>
#include <fstream>
#include <stdio.h>
#include <cstring>
#include <strings.h>

using namespace std;

struct record
{
    char first [20];
    char mid   [1];
    char last  [20];
    int  ssn;
};

void filename (char ifname [], struct record* student[]);
void structfill (fstream & infile, struct  record*  student []);

int main ()
{

    system ("clear");

    fstream infile;
    char ifname [256];
    struct record * student;
    filename (ifname, student);

    return 0;
}
/*******************************************************************/
void filename (char ifname [],record* student [])
{
    fstream infile;
    cout << "Enter name of file to read from: ";
    cin.getline (ifname, 256);
    cout << endl;
    infile.open (ifname);
    if (!infile.is_open ())
    {
        cerr << "FILELOOP!: Unable to open input file " << ifname
        << endl;
        exit (1);
    }
    structfill (infile, student);
}
/*******************************************************************/
void structfill (fstream & infile, record* student [])
{

    char buffer [81];
    char buffername [81];
    char bufferfirst [81];
    int n=0;
    int x=0;
    int f=0;

    infile.getline (buffer,81);
    while (!infile.eof ())
    {
        x++;
        cout << "-----------------------" << x;
        if (strncasecmp (buffer, "<student>",9)==0)
        {
            n++;
            cout << "jess sucks" << n;
            student = new *record;
            infile.getline (buffername, 81);
            if (strncasecmp (buffername, "<first>",7)==0)
            {
                f++;
                infile.getline (bufferfirst, 81);
                strcpy (student->first, bufferfirst);
                cout << endl << "######  " << f;
            }
        }
        infile.getline (buffer, 81);
        cout << *student[n]->first;
        cout << "endendendend" << endl;
    }
}

Answer 1

传递时，数组衰减为指向第一个元素的指针：

void structfill (fstream & infile, record*  student);

此外，删除C-isms。不需要在这里指定"struct“。

Answer 2

这是没有错误的代码，我编译成功了

#include <iostream>
#include <cstdlib>
#include <fstream>
#include <stdio.h>
#include <cstring>
#include <strings.h>


using namespace std;

struct record
{
    char first [20];
    char mid   [1];
    char last  [20];
    int  ssn;
};

void filename (char ifname [], struct record* student);
void structfill (fstream & infile, struct  record*  student);

int main ()
{

    system ("clear");

    fstream infile;
    char ifname [256];
    struct record * student;
    filename (ifname, student);

    return 0;
}
/*******************************************************************/
void filename (char ifname [],record* student )
{
    fstream infile;
    cout << "Enter name of file to read from: ";
    cin.getline (ifname, 256);
    cout << endl;
    infile.open (ifname);
    if (!infile.is_open ())
    {
        cerr << "FILELOOP!: Unable to open input file " << ifname
        << endl;
        exit (1);
    }
    structfill (infile, student);
}
/*******************************************************************/
void structfill (fstream & infile, record* student )
{

    char buffer [81];
    char buffername [81];
    char bufferfirst [81];
    int n=0;
    int x=0;
    int f=0;

    infile.getline (buffer,81);
    while (!infile.eof ())
    {
        x++;
        cout << "-----------------------" << x;
        if (strncasecmp (buffer, "<student>",9)==0)
        {
            n++;
            cout << "jess sucks" << n;
            student = new struct record;
            infile.getline (buffername, 81);
            if (strncasecmp (buffername, "<first>",7)==0)
            {
                f++;
                infile.getline (bufferfirst, 81);
                strcpy (student->first, bufferfirst);
                cout << endl << "######  " << f;
            }
        }
        infile.getline (buffer, 81);
        cout << student[n].first;
        cout << "endendendend" << endl;
    }
}

1. object.You运算符返回指针不应使用结构record.
2. student能够保存一个结构记录数组。