为什么Xcode6.0.1中的iOS 8.0模拟器无法正确获取cookie

Question

在升级到Xcode6之后，当我从登录"POST“操作中获取cookie时，如下所示：

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://%@/login.php", kDSZHDomainString]];
ASIFormDataRequest *asirequest = [ASIFormDataRequest requestWithURL:url];
[asirequest setPostValue:username forKey:@"u"];
[asirequest setPostValue:password forKey:@"p"];
[asirequest setTag:kLoginRequest];
[asirequest setStringEncoding:-2147481083];
[asirequest setTimeOutSeconds:600];
[asirequest setDelegate:self];
[asirequest startAsynchronous]; 

当我设置断点来获取请求的头部时：

NSMutableDictionary * headers = [request requestHeaders];

调试信息：

Printing description of headers:
{
    "Accept-Encoding" = gzip;
    "Content-Length" = 20;
    "Content-Type" = "application/x-www-form-urlencoded; charset=hz-gb-2312";
    Cookie = "__utma=213790228.284667840.1411460847.1411460847.1411460847.1; __utmz=213790228.1411460847.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); o=m; s=542366a13a44e; sv[1]=12532852%2C12532147%2C12534523; v[11]=12515374; v[1]=12534523; v[2]=12521992; v[3]=12527199; v[9]=12441637";
    "User-Agent" = "Top81 0.7 rv:0.7.459 (iPhone Simulator; iPhone OS 8.0; en_US)";
}

在iOS 7模拟器中，标头是：

Printing description of headers:
{
    "Accept-Encoding" = gzip;
    Cookie = "o=m; s=542369d4ede78; sv[1]=12532886%2C12528442%2C12534551; u=xxxx%2Ca999b1c0d3663e236f58277302b8be90%2C0; v[1]=12534551";
    "User-Agent" = "Top81 0.7 rv:0.7.459 (iPhone Simulator; iPhone OS 7.1; en_US)";
}

因此，cookie "u“已正确获取。

我用ASIHTTPRequest和AFNetworking测试了代码，得到了相同的结果。

是Xcode和iOS 8模拟器的错误还是解决这个问题的任何代码？

Answer 1

我已经使用了afnetworking，它在ios 8中运行良好。

+(void)postData : (NSString *)url parameters:(NSDictionary *)paraDict  success: (void (^) (NSDictionary *responseStr))success failure: (void (^) (NSError *error))failure
{
    AFHTTPRequestOperationManager *manager = [[AFHTTPRequestOperationManager alloc] initWithBaseURL:[NSURL URLWithString:url]];

    manager.responseSerializer =  [AFHTTPResponseSerializer serializer];

    AFHTTPRequestOperation *op = [manager POST:url parameters:paraDict constructingBodyWithBlock:^(id<AFMultipartFormData> formData) {

    } success:^(AFHTTPRequestOperation *operation, id responseObject)
    {
        NSError* error = nil;


        success([NSJSONSerialization JSONObjectWithData:responseObject options:0 error:&error]);

    } failure:^(AFHTTPRequestOperation *operation, NSError *error) {

        failure(error);
    }];
    [op start];

}

这里的url是字符串而不是nsurl，它应该类似于@"http://www.google.com“

paradict是字典。你可以把它写成

NsDictionary *paraDict =@{@“用户名”：@“u”，@“密码”：@“p”}

希望能有所帮助