我有以下NSCharacterSet,并希望生成一个对该字符集有效的随机字符串。
NSMutableCharacterSet *characterSet = [NSMutableCharacterSet alphanumericCharacterSet];
[characterSet formUnionWithCharacterSet:[NSCharacterSet whitespaceCharacterSet]];[NSCharacterSet characterSetWithCharactersInString:]从字符串中生成字符集。我想要一个做相反事情的方法。像[NSString stringWithCharacterSet:]这样的东西
发布于 2014-09-24 20:43:38
我不认为NSCharacterSet是存储有效字符列表的最佳方法,因为它没有提供方便的方法来获取长度或访问特定索引处的字符。请改用NSString:
+ (NSString *)randomStringFromCharacters:(NSString *)chars
ofLength:(NSUInteger)length
{
unichar str[length];
for (NSUInteger i = 0; i < length; i++)
str[i] = [chars characterAtIndex:arc4random() % [chars length]];
return [NSString stringWithCharacters:str length:length];
}https://stackoverflow.com/questions/26016931
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