C#中十六进制的浮点数

Question

我在谷歌上发现，关于如何将数字转换为十六进制浮点单精度，“切中要害”的信息并不多。有三个明确的步骤:1转换整个二进制部分。2添加逗号并将小数部分转换为二进制。3将结果放在科学报告中。4将结果传递给IEEE-754标准32位。这将导致二进制。然后将其转换为十六进制。这一切都很糟糕，我把代码放在这里，希望它能为我解决这个问题；-)问候你。

      private String Float2Hex(String value) {
        String[] aux;
        String number = "", mantissa = "", exponent = "";
        Double div = 0;
        int exp = 0;
        aux = value.Split('.');
        number = Convert.ToString(int.Parse(aux[0]), 2);
        exp = number.Length - 1;

        mantissa = number.Substring(1, number.Length - 1);

        while ((aux.Length > 1) && (mantissa.Length < 23)) {
            div = Double.Parse("0," + aux[1]) * 2;
            aux = div.ToString().Split(',');
            mantissa += aux[0];
        }

        while (mantissa.Length < 23)    // Simple precision = 23 bits
            mantissa += "0";

        exponent = Convert.ToString(exp + 127, 2);

        if (value.Substring(0, 1).Equals("-"))
            number = "1" + exponent + mantissa;
        else
            number = "0" + exponent + mantissa;

        return Bin2Hex(number);
    }

我使用另一个合作伙伴的以下Bin2Hex函数：Binary to Hexadecimal

Answer 1

另一个例子：

        String value = "", tmp = "";

        val = float.Parse(StringValue);

        byte[] b = BitConverter.GetBytes(val);
        StringBuilder sb = new StringBuilder();

        foreach (byte by in b)
            sb.Append(by.ToString("X2"));

        return sb.ToString();            

Answer 2

你能不能不使用流来写浮点值？

string a = Float2Hex(4.5f);

函数

public string Float2Hex(float fNum)
{
    MemoryStream ms = new MemoryStream(sizeof(float));
    StreamWriter sw = new StreamWriter(ms);

    // Write the float to the stream
    sw.Write(fNum);
    sw.Flush();

    // Re-read the stream
    ms.Seek(0, SeekOrigin.Begin);
    byte[] buffer = new byte[4];
    ms.Read(buffer, 0, 4);

    // Convert the buffer to Hex
    StringBuilder sb = new StringBuilder();
    foreach (byte b in buffer)
        sb.AppendFormat("{0:X2}", b);

    sw.Close();

    return sb.ToString();
}