查询:显示当月开票超过4张的业务员姓名

Question

PostgreSQL查询:显示当月开票超过4张的业务员姓名。

表格：articles, customers, invoices, lines_invoice, province, towns, sellers。

我的查询返回值而不考虑计数在同一个月，我如何做到这一点？

select s.codseller, s.name 
from sellers s 
join invoices i using (codseller) 
group by s.codseller 
having count (codinvoice) > 4;

谢谢!

编辑：

屏幕上显示的正确解决方案是：

​

codven =代码销售者名称= name

在我的查询中，它显示了额外的两行，因为它计算了超过4张发票的销售人员，但在不同的月份。

Answer 1

SELECT s.id, s.name
      ,date_trunc('month', i.sales_date::timestamp) AS month
      ,COUNT(i.id) AS invoices_for_month
  FROM seller s
  INNER JOIN invoices i ON (s.id = i.seller_id)
  GROUP BY s.id, s.name, date_trunc('month', i.sales_date::timestamp)
  HAVING COUNT(i.id) > 4

测试的环境是：

CREATE TABLE seller (id int, name text);
INSERT INTO seller VALUES(1, 'Joe');
INSERT INTO seller VALUES(2, 'Mike');
INSERT INTO seller VALUES(3, 'Tom');

CREATE TABLE invoices(id int, seller_id int, sales_date date);
INSERT INTO invoices VALUES(1, 1, now());
INSERT INTO invoices VALUES(2, 1, now() - interval '35' day);
INSERT INTO invoices VALUES(3, 1, now() - interval '37' day);
INSERT INTO invoices VALUES(4, 1, now() - interval '39' day);
INSERT INTO invoices VALUES(5, 1, now() - interval '40' day);
INSERT INTO invoices VALUES(6, 1, now() - interval '40' day);
INSERT INTO invoices VALUES(7, 2, now());

Answer 2

我把答案留在这里，但Glenn的答案更好

您必须提取group_by子句中的月份(未经测试)：

select s.codseller, 
EXTRACT(MONTH FROM i.date) as month, 
EXTRACT(YEAR FROM i.date) as year, s.name 
from sellers s 
join invoices i using (codseller) 
group by s.codseller, month, year
having count (codinvoice) > 4;

也请看一下How do I group by month and year when only having a datetime field?

您还应该看看postgresqls datetime functions。