在music21中创建便笺的图像

Question

运行时出现错误：

from music21 import *

n1 = note.Note('C4', quarterLength=1)
n2 = note.Note('A4', quarterLength=1)
s = stream.Stream()
s.append(n1)
s.append(n2)
s.show('lily.svg')

Traceback (most recent call last):
  File "C:\Python34\test.py", line 7, in <module>
    s.show('lily.svg')
  File "C:\Python34\lib\site-packages\music21\base.py", line 2206, in show
    return formatWriter.show(self, regularizedConverterFormat, app=app, subformats=subformats, **keywords)
  File "C:\Python34\lib\site-packages\music21\converter\subConverters.py", line 277, in show
    returnedFilePath = self.write(obj, fmt, subformats=subformats, **keywords)
  File "C:\Python34\lib\site-packages\music21\converter\subConverters.py", line 245, in write
    conv = lily.translate.LilypondConverter()
  File "C:\Python34\lib\site-packages\music21\lily\translate.py", line 147, in __init__
    self.setupTools()
  File "C:\Python34\lib\site-packages\music21\lily\translate.py", line 177, in setupTools
    versionString = versionString.split()[-1]
IndexError: list index out of range

我已经安装了scipy和mathplotlib，所以music21不会再抱怨它们不可用了。我在Windows7上运行Python 3.4。

如果我使用s.show('musicxml.png')来获取我的图像，我会得到错误：

Traceback (most recent call last):
  File "C:\Python34\test.py", line 7, in <module>
    s.show('musicxml.png')
  File "C:\Python34\lib\site-packages\music21\base.py", line 2206, in show
    return formatWriter.show(self, regularizedConverterFormat, app=app, subformats=subformats, **keywords)
  File "C:\Python34\lib\site-packages\music21\converter\subConverters.py", line 147, in show
    returnedFilePath = self.write(obj, fmt, subformats=subformats, **keywords)
  File "C:\Python34\lib\site-packages\music21\converter\subConverters.py", line 637, in write
    fp = self.runThroughMusescore(fp, **keywords)
  File "C:\Python34\lib\site-packages\music21\converter\subConverters.py", line 606, in runThroughMusescore
    elif not os.path.exists(musescoreFile):
  File "C:\Python34\lib\genericpath.py", line 19, in exists
    os.stat(path)
TypeError: stat: can't specify None for path argument

我必须做什么才能得到图片(最好是svg)？

Answer 1

LILYPOND

我也犯了同样的错误。我已经设法通过以下方式为music21配置了LilyPond：

1. 将LilyPond文件夹移至不带空格的路径(从C:\Program Files (x86)\LilyPond\usr\bin移至C:\LilyPond\usr\bin)。我在lilypond代码中看到，在执行way.
2. Created configuration file in music21 and set lilypondPath命令时，它没有在path周围设置必要的配额，所以必须在这个music21中解决这个问题

us = environment.UserSettings() us.create() us‘’lilypondPath‘=’C:/‘lilypondPath/usr/bin/lilypond.exe’

您可以检查是否设置正确：

print us'lilypondPath'

• Well，这可能不是必须的，但在我尝试的过程中，我重新启动了几次，所以如果所有东西都不工作，你可以在最后尝试一下。immediately.

MUSESCORE

1. 以防万一，将Musescore安装到不带空格的路径中(
2. 在环境中添加了两次musescore路径(发现了这种设置环境变量的新方法)，一次是作为"musescoreDirectPNGPath"environment.set("musescoreDirectPNGPath", "C:/MuseScore2/bin/MuseScore.exe")

然后作为"musicxmlPath"environment.set("musicxmlPath", "C:/MuseScore2/bin/MuseScore.exe")

• After几次尝试，调试等。我了解到，如果我们想使用Musescore，传入文件扩展名'.xml‘而不是'.png’是很重要的：

stream_name.show('musicalxml.xml')

Musescore无法打开.png文件，但它可以打开.xml文件。

最后，我可以添加一些无需打开lilypond或musescore即可生成文件的代码。希望有人觉得它很有用

LILYPOND：

# music21object - stream or score or any object that can be showed
conv =  music21.converter.subConverters.ConverterLilypond()
scorename = 'myScoreName'
filepath = 'C:/path/to/musical_scores/' + scorename
conv.write(music21object, fmt = 'lilypond', fp=filepath, subformats = ['pdf'])

MUSESCORE：

from music21.converter.subConverters import ConverterMusicXML
conv_musicxml = ConverterMusicXML()
scorename = 'myScoreName.xml'
filepath = 'C:/path/to/musical_scores/' + scorename
out_filepath = conv_musicxml.write(music21object, 'musicxml', fp=filepath, subformats=['png'])

注意，scorename有'.xml‘扩展名。

遗憾的是，它不会将文件保存在指定的文件路径中。Musescore将"-1“添加到文件名中，但可以获得更改后的文件路径(如上面代码中的out_filepath )，并在稍后重命名为我们想要的名称。

Answer 2

我可以用一个带空格的路径来设置musescore。最重要的是要确保使用反斜杠。我是这样做的：

# Create the user environment for music21
us = m21.environment.UserSettings()
us['musicxmlPath'] = 'C:/Program Files (x86)/MuseScore 2/bin/MuseScore.exe'
us['musescoreDirectPNGPath'] = 'C:/Program Files (x86)/MuseScore 2/bin/MuseScore.exe'

希望它能帮上忙！