我正在制作一个网站,我有一个signup.php页面,在那里用户可以注册和输入他们的信息到mysqli数据库。当我这样做的时候,我几乎就在那里,我只是在这一行上不断地遇到问题:
ajax.send("&u="+u+"&e="+e+"&p="+p1+"&g="+g);它主要是发送ajax/javascript检查中的变量,以便为传输到服务器做好准备。但是我在那条线路上得到了一个内部服务器500错误。有什么想法吗?我会张贴更多的代码,如果你想我。
function ajaxReturn(x){
if(x.readyState == 4 && x.status == 200){
return true;
}
}
function signup(){
var u = _("username").value;
var e = _("email").value;
var p1 = _("pass1").value;
var p2 = _("pass2").value;
var g = _("gender").value;
var status = _("status");
if(u == "" || e == "" || p1 == "" || p2 == "" || g == ""){
status.innerHTML = "Fill out all of the form data";
} else if(p1 != p2){
status.innerHTML = "Your password fields do not match";
} else {
_("signupbtn").style.display = "none";
status.innerHTML = 'please wait ...';
var ajax = ajaxObj("POST", "signup.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText != "signup_success"){
status.innerHTML = ajax.responseText;
_("signupbtn").style.display = "block";
} else {
window.scrollTo(0,0);
_("signupform").innerHTML = "OK "+u+", check your email inbox and junk mail box at <u>"+e+"</u> in a moment to complete the sign up process by activating your account. You will not be able to do anything on the site until you successfully activate your account.";
}
}
}
type:post;
ajax.send("&u="+u+"&e="+e+"&p="+p1+"&g="+g);
}}
发布于 2013-10-17 10:00:41
内部服务器错误代码500是HTTP响应代码,表示您已联系到服务器,并且服务器已返回错误。所以你的JS代码看起来不是问题(至少从你发布的内容来看是这样)。
尝试将var_dump($_REQUEST); die();作为signup.php中的第一行。这会给你一个200的状态码吗?如果是这样,请尝试在服务器上将该行代码向下移动,直到返回到500Internal server错误,您就找到了导致问题的行。
您的问题标记为jQuery,但我在您的代码示例中没有看到任何jQuery。如果你有,试试这个:
function signup() {
var status = $('#status');
var signupbtn = $('#signupbtn');
var data = {
u: $('#username').val(),
e: $('#email').val(),
p: $('#pass1').val(),
g: $('#gender').val()
};
if (data.u == '' || data.e == '' || data.p == '' || data.g == '') {
status.text('Fill out all of the form data');
return;
} else if (data.p != $('#pass2').val()) {
status.text('Your password fields do not match');
return;
}
signupbtn.hide();
status.text('please wait...');
$.ajax({
type: 'post',
url: 'signup.php',
data: data,
success: function(responseText) {
if (responseText != 'signup_success') {
status.text(responseText);
signupbtn.show();
return;
}
window.scrollTo(0, 0);
$('#signupform').html('OK '+ data.u +', check your email inbox and junk mail box at <u>'+ data.e +'</u> in a moment to complete the sign up process by activating your account. You will not be able to do anything on the site until you successfully activate your account.');
},
});
}https://stackoverflow.com/questions/19416847
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