如何返回某个特定unix-timestamp PHP一个月开始的unix-timestamp

Question

我需要一个泛型函数，它接受日期-时间的unix-timestamp表示，并返回一个表示，比方说，每月第一天午夜的表示。

即传递表示now (清华，2012 12: 01 :33 GMT)的1352376093，返回表示(清华，2012年11月01 00:00:00 )的1351728000

Answer 1

这段代码应该可以帮助您解决这个问题。只需从现有日期中获取月份和年份，并将其转换回时间戳。

<?php
     $time = 1352376093;
     $date = date('Y-m-01 00:00:00', $time);
     $result = strtotime($date);

Answer 2

所以最终得到了这个函数：

$earliest_issue = db_result( $result, 0 );
$day_of_month_of_earliest_issue = date("d", $earliest_issue);
$hour_of_month_of_earliest_issue = date("h", $earliest_issue);
$minute_of_month_of_earliest_issue = date("i", $earliest_issue);
$seconds_in_month = date("s", $earliest_issue);
$seconds_in_day_of_month = (($day_of_month_of_earliest_issue*24*60*60)-86400);
$seconds_in_hour_of_month = (($hour_of_month_of_earliest_issue*60*60)-3600);
$seconds_in_minute_of_month = (($minute_of_month_of_earliest_issue*60));
$start_time_of_query = ($earliest_issue - $seconds_in_day_of_month - $seconds_in_hour_of_month - $seconds_in_minute_of_month - $seconds_in_month);

return $start_time_of_query;

其中$earliest_issue是开始日期...

如果阅读这篇文章的人有我所希望的更优雅的功能，请贡献给我，谢谢！