Tac Tac Toe游戏错误

Question

我编写了一个tic tac toe游戏，它编译和运行良好，但如果你点击左上角的方框，它会自动显示X赢得Like this。这是棋盘上唯一能做到这一点的运动。不确定我在决定获胜者时做错了什么。如果你想看更多的代码，完整的代码是here。

        //Determine who won
        if(button1.getText() == button2.getText()
                && button2.getText() == button3.getText()
                && button1.getText() != "")
        {
            win = true;
        }
        else if(button4.getText() == button5.getText()
                    && button5.getText() == button6.getText()
                    && button4.getText() != "")
        {
            win = true;
        }
        else if(button7.getText() == button8.getText()
                    && button8.getText() == button9.getText()
                    && button7.getText() != "")
        {
            win = true;
        }

        else if(button1.getText() == button4.getText()
                    && button4.getText() == button7.getText()
                    && button1.getText() != "")
        {
            win = true;
        }
        else if(button2.getText() == button5.getText()
                    && button5.getText() == button8.getText()
                    && button2.getText() != "")
        {
            win = true;
        }
        else if(button3.getText() == button6.getText()
                        && button6.getText() == button9.getText()
                        && button3.getText() != "")
        {
                win = true;
        }
        else if(button1.getText() == button5.getText()
                    && button5.getText() == button9.getText()
                    && button1.getText() != "")
        {
            win = true;
        }
        else if(button3.getText() == button5.getText()
                    && button5.getText() == button7.getText()
                    && button1.getText() != "")
        {
            win = true;
        }
        else
        {
            win = false;
        }

        if (win == true)
        {
            JOptionPane.showMessageDialog(null,
                                          letter + " Wins!");
        }
        else if (count == 9 && win == false)
        {
            JOptionPane.showMessageDialog(null,
                                          "Tie Game!");
        }
    }
}

Answer 1

不要使用==和!=比较字符串。请改用equals()和!equals()。

请参阅How do I compare strings in Java?