循环和计数器的C程序设计

Question

我正在尝试编写一个程序来计算你需要多少个州才能获胜。我已经完成了主要部分，但现在我正在尝试创建一个FOR循环，它基本上检查您现在拥有的票数加上该州拥有的票数之和是否大于270，即获胜的票数。在那之后，我试着打印，如果你赢了这个州，你就会赢。最后，它将计算并打印出您可以获胜的方法。到目前为止，这就是我所知道的，但当我调用它们时，它没有说出州的名称，它也没有给我一个1，2或3个数字来表示你能赢的方式，只给了一个我没有存储的大数字。

有谁可以帮我？

#include <stdio.h>

int main(void){

    //Initialize your variables
    int current_votes, num_votes_1, num_votes_2, x;
    char name_state_1, name_state_2;


    //ask the user for the current number of electoral votes their candidate has
    printf("How many electoral votes has your candidate won?\n");
    scanf("%d", &current_votes);

    //Now ask for the first state in contention
    printf("What is the name of the first state in contention?\n");
    scanf("%s", &name_state_1);

    //now ask hiw many electoral votes the first state has
    printf("How many electoral votes does it have?\n");
    scanf("%d", &num_votes_1);

    //now ask for the second state in contention
    printf("What's the name of the second state in contention?\n");
    scanf("%s", &name_state_2);

    //now ask how many electoral votes the second state has
    printf("How many electoral votes does it have?\n");
    scanf("%d", &num_votes_2);

    //Now here's the formula that checks to see if you win in each state
    //and counts how many ways you can win
    for(x = 0; x < 3; x++) {
        if(current_votes + num_votes_1 >= 270);
            printf("Your candidate wins if he/she wins %s", &name_state_1);
            x++;
        if(current_votes + num_votes_2 >= 270);
            printf("Your candidate wins if he/she wins %s", &name_state_2);
            x++;
        if(current_votes + num_votes_1 + num_votes_2 >= 270);
            printf("your candidate wins if he/she wins %s", &name_state_1, &name_state_2);
            x++;

    }
    //now call to tell how many ways the candidate can win overall
    printf("your candidate can win %d ways", &x);
    return 0;

}

Answer 1

您的if包含空语句

if(current_votes + num_votes_1 >= 270);

删除;

而且，c不像python，缩进不会使代码成为if块的一部分。

if(current_votes + num_votes_1 >= 270)
    printf("Your candidate wins if he/she wins %s", &name_state_1);
    x++;

将始终执行x++。只有printf部分是if块的一部分。使用{}封装代码。

最后，您还打印了x的地址，这就是它是一个大数字的原因。最后，使用x来计算获胜的方式并作为循环条件并不是一个好主意。在我看来，你甚至不需要这个循环。

这似乎足够了：

x = 0;
if(current_votes + num_votes_1 >= 270);
{
    printf("Your candidate wins if he/she wins %s", &name_state_1);
    x++;
}

if(current_votes + num_votes_2 >= 270);
{
    printf("Your candidate wins if he/she wins %s", &name_state_2);
    x++;
}

if(current_votes + num_votes_1 + num_votes_2 >= 270);
{
    printf("your candidate wins if he/she wins %s", &name_state_1, &name_state_2);
    x++;
}