我正在解析robots.txt文件,并且我已经编写了解析器来成功解析“格式良好”的robots.txt文件。我已经能够调整解析器以跳过以符号(如#或/代表注释)开头的行,但只能使用inClass "#/"。
我一直无法解决的一个问题是,如果一行不包含我想要匹配的字符串,则跳过该行。
User-agent: *
Disallow: /includes/
Disallow: /misc/
Disallow: /modules/
Doesn't belong here
Disallow: /profiles/
Disallow: /scripts/
Disallow: /themes/我首先尝试使用以下命令进行匹配:
satisfy (notInClass "DdUu") *> skipWhile (not . isEndOfLine)
我认为这样做会消除我对特定注释行解析器的需求,因为散列或斜杠不会落入字符类。问题是,这不起作用。
我也意识到,如果它工作了,它无论如何也不会工作,因为它不能解决像“不允许”这样的匹配问题。“不允许”。
以下是解析代码(没有注释跳过代码,这只适用于格式良好的robots.txt):
{-# LANGUAGE OverloadedStrings, RankNTypes #-}
import Prelude hiding (takeWhile)
import Control.Applicative hiding (many)
import Data.Char
import Data.Text as T hiding (toLower)
import Data.Text.Encoding as E
import Control.Monad
import Data.Attoparsec.ByteString
import qualified Data.Attoparsec.Char8 as AC
import Data.Array.Unboxed
import Data.ByteString as B hiding (takeWhile)
import qualified Data.ByteString.Internal as BI
import Data.Word (Word8)
type RuleMap = [(ByteString, ByteString)]
-- newtype for indexable ua
newtype UserAgent = UserAgent { unUA :: ByteString }
deriving (Eq, Ord, Show)
data RuleSet = RuleSet
{ userAgent :: UserAgent,
rules :: RuleMap }
deriving (Eq, Ord, Show)
main = do
r <- B.readFile "/Users/ixmatus/Desktop/robots.txt"
print $ parse (many1 parseUABlock) r
stripper = E.encodeUtf8 . T.strip . E.decodeUtf8
isNotEnd = not . AC.isEndOfLine
-- | Catch all character matching, basically
matchALL :: Word8 -> Bool
matchALL = inClass ":/?#[]@!$&'()*%+,;=.~a-zA-Z0-9 _-"
-- | @doParse@ Run the parser, complete the partial if the end of the stream has
-- a newline with an empty string
doParse :: ByteString -> [RuleSet]
doParse cont =
case parse (many1 parseUABlock) cont of
Done _ set -> set
Partial f -> handlePartial (f B.empty)
Fail {} -> []
-- | @handlePartial@ Handle a partial with empty string by simply
-- returning the last completion
handlePartial :: forall t a. IResult t [a] -> [a]
handlePartial (Done _ r) = r
handlePartial (Fail {}) = []
-- | @parseUABlock@ Parse a user-agent and rules block
parseUABlock = do
ua <- parseUACol *> uA
rulez <- many1 parseRules
return RuleSet { userAgent = UserAgent ua,
rules = rulez }
-- | @matchUACol@ Parse the UA column and value taking into account
-- possible whitespace craziness
parseUACol = AC.skipSpace
*> AC.stringCI "User-Agent"
<* AC.skipSpace
*> AC.char8 ':'
*> AC.skipSpace
uA = do
u <- takeWhile1 isNotEnd
return (stripper u)
-- | @parseRules@ Parse the directives row
parseRules = (,) <$> parseTransLower
<*> directiveRule
directiveRule = do
rule <- takeWhile1 matchALL <* many1 AC.endOfLine
return (stripper rule)
parseTransLower = do
res <- parseDirectives <* AC.skipSpace
return (lowercase res)
ctypeLower = listArray (0,255) (Prelude.map (BI.c2w . toLower) ['\0'..'\255']) :: UArray Word8 Word8
lowercase = B.map (\x -> ctypeLower!x)
directives = AC.stringCI "Disallow" <|> AC.stringCI "Allow"
-- | @parseDirectives@ Parse the directive column and any possibly
-- funny whitespace
parseDirectives = AC.skipSpace
*> directives -- <|> AC.stringCI "Crawl-delay" <|> AC.stringCI "Sitemap")
<* AC.skipSpace
<* AC.char8 ':'发布于 2013-04-10 13:08:53
考虑这种方法。
定义:
data RobotsDirective = RobotsDirective String String这表示robots.txt文件中已解析的指令。第一个字符串是指令(即UserAgent、Allow、Disallow等)。第二个字符串是冒号后面的东西。
现在为RobotsDirective编写一个解析器
parseRD :: Parser RobotsDirectiveparseRD将查找指令名称(应该只包含字母、数字和破折号,可能还有下划线),后跟一个冒号,后跟零个或多个非换行符。适当地忽略空格。如果parseRD找到这样的模式,它将创建并返回一个RobotsDirective。否则,它将跳过一行字符并重试。
现在您已经有了一个用于RobotsDirective的解析器,您可以用标准方式创建一个用于[RobotsDirective]的解析器。
这个解析器简单地跳过任何看起来不像指令的行,这将包括空行、注释行和以Don't allow...开头的行。但是,对于robots.txt文件中无效的行,它可能会返回一个RobotsDirective,即:
foo: blah将返回RobotsDirective "foo" "blah"。在解析robots.txt文件并获得RobotsDirective值的列表之后,只需遍历该列表并忽略您不感兴趣的值。
https://stackoverflow.com/questions/15912086
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