php-include之后不显示任何内容

Question

我正在尝试将一个php文件包含在另一个文件中(作为第一件事)，因为我需要变量，这些变量是MySQL语句的结果。以下是包含以下内容的文件：

index.php：

 <?php 
    error_reporting(E_ALL); //No errors are shown
    require($_SERVER['DOCUMENT_ROOT']."php/db/acp_settings_db_conn.php");
    echo $_SERVER['DOCUMENT_ROOT']; //doesn't work
    ?> /*  * some html code, which isn't shown either  */

这是get包含的文件：

<?php
//Get configuration values (static) from file
require_once($_SERVER['DOCUMENT_ROOT']."acp_settings_db_conf.php");
//Create new object out of connection to db
$db = @new mysqli(MYSQL_HOST, MYSQL_USER, MYSQL_PASS, MYSQL_DB);
//If there aren't any errors
if(mysqli_connect_errno() == 0){
    //Write query, in this case get every row from table
    $query = 'SELECT * FROM `meta`';
    //If you could prepare query
    if($meta_settings = $db->prepare( $query )){
        //Execute query
        $meta_settings->execute();          
        //Bind results to custom variables
        $meta_settings->bind_result($html_language, $site_author, $site_keywords);  
        //Fetch result
        $meta_settings->fetch();
    } else { //If you couldn't prepare query
        echo "There is a problem with the query";
    }

} else { //If you couldn't connect to DB at all
    die("No connection possible: " . mysqli_connect_error());
}
//Close connection
$db->close();
?>

包含的文件工作得很好(用回显检查)，现在包含也可以工作了(如果我在包含的文件中有回显的东西，它会在index.php上弹出)。但在包含之后，将不会显示任何其他内容。所以没有php-code在工作，也没有显示任何html。我尝试了一个包含'file.php'，但它不起作用。

既然我把晚上都花在这上面了，如果有人能帮我，我会很高兴。这些是我在PHP中的第一步，所以要轻柔一些;)

Answer 1

尝试添加DIRECTORY_SEPARATOR。

require($_SERVER['DOCUMENT_ROOT'] . DIRECTORY_SEPARATOR . "php/db/acp_settings_db_conn.php");