如何将Spring Boot应用程序部署到Tomcat 6 Servlet 2.5

Question

我使用spring boot创建了一个常见问题解答。它需要部署到Tomcat6服务器(Servlet2.5)上。我需要配置当前的父java应用程序(War) web.xml，以将所有请求指向url模式"/ FAQ /*“，例如指向我的spring boot常见问题应用程序。我已经将FAQ.jar文件复制到父应用程序的lib文件夹中。但是我不确定如何在父应用程序的web.xml中配置/注册spring boot servlet和servlet映射。

使用spring boot遗留示例..我将我的spring boot应用程序与依赖jar文件放在父应用程序库文件夹中。我将此代码块添加到父应用程序的web.xml中。

 <context-param>
     <param-name>contextConfigLocation</param-name>
     <param-value>faq.Application</param-value>
 </context-param>

  <listener>
      <listener-class>
          org.springframework.boot.legacy.context.web.SpringBootContextLoaderListener
      </listener-class>
  </listener>

  <filter>
      <filter-name>metricFilter</filter-name>
      <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
  </filter>

<filter-mapping>
    <filter-name>metricFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<servlet>
    <servlet-name>SpringServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextAttribute</param-name>
        <param-value>org.springframework.web.context.WebApplicationContext.ROOT</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>SpringServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

但是当我启动Tomcat时，我得到了以下错误。

Jun 30,2014 12:17:23 AM org.apache.catalina.core.StandardContext listenerStart SEVERE:向类的侦听器实例发送上下文初始化事件时出现异常java.lang.IllegalAccessError:尝试访问方法org.springframework.core.io.support.SpringFactoriesLoader.loadFactoryNames(Ljava/lang/Class;Ljava/lang/ClassLoader;)Ljava/util/List；从org.springframework.boot.SpringApplication.getSpringFactoriesInstances(SpringApplication.java:355)在org.springframework.boot.SpringApplication.getSpringFactoriesInstances(SpringApplication.java:346)在org.springframework.boot.SpringApplication.initialize(SpringApplication.java:222)在org.springframework.boot.SpringApplication.(SpringApplication.java:198)在org.springframework.boot.builder.SpringApplicationBuilder.(SpringApplicationBuilder.java:83)在org.springframework.boot.legacy.context.web.SpringBootContextLoaderListener的org.springframework.boot.SpringApplication班级.initWebApplicationContext(SpringBootContextLoaderListener.java:48)在org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:47)在org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4779)在org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5273)在org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)在org.apache.catalina.core.ContainerBase.addChildInternal(ContainerBase.java:897)在org.apache.catalina.core.ContainerBase.addChild(ContainerBase.java:873) at org.apache.catalina.core.StandardHost.addChild(StandardHost.java:615) at org.apache.catalina.startup.HostConfig.deployDirectory(HostConfig.java:1095) at org.apache.catalina.startup.HostConfig$DeployDirectory.run(HostConfig.java:1617) at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:441) at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:303) at java.util.concurrent.FutureTask.run(FutureTask.java:138) at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) at java.lang.Thread.run(Thread.java:619) 6月30日，2014 12:17:23 AM org.apache.catalina.core.StandardContext startInternal严重: Error listenerStart

KevyKev

Answer 1

Spring Boot并不正式支持Servlet 2.5，但它并不需要花费太多时间就能使其工作。您可能会发现这很有用：https://github.com/scratches/spring-boot-legacy。示例如下：https://github.com/scratches/spring-boot-sample-gae。