我一直在使用NSDataDetector从字符串中解析出地址,大多数情况下它都做得很好。然而,在类似于这个地址的地址上,它没有检测到它。
6200 North Evan Blvd Suit 487 Highland UT 84043
目前,我正在使用以下代码:
NSError *error = nil;
NSDataDetector *detector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeAddress error:&error];
NSArray *matches = [detector matchesInString:output options:0 range:NSMakeRange(0, [output length])];
for (NSTextCheckingResult *match in matches) {
if ([match resultType] == NSTextCheckingTypeAddress) {
_address = [_tesseractData substringWithRange:[match range]];
NSDictionary *data = [match addressComponents];
_zip = [data objectForKey:@"ZIP"];
if (_zip) {
NSRange zipRange = [_tesseractData rangeOfString:_zip];
if (zipRange.location != NSNotFound) {
[_tesseractData deleteCharactersInRange:zipRange];
}
}
_city = [data objectForKey:@"City"];
if (_city) {
NSRange cityRange = [_tesseractData rangeOfString:[_city uppercaseString]];
if (cityRange.location != NSNotFound) {
[_tesseractData deleteCharactersInRange:cityRange];
}
}
_city = [_city capitalizedString];
_state = [data objectForKey:@"State"];
_street = [data objectForKey:@"Street"];
if (_street) {
NSRange streetRange = [_tesseractData rangeOfString:[_street uppercaseString]];
if (streetRange.location != NSNotFound) {
[_tesseractData deleteCharactersInRange:streetRange];
}
}
_street = [_street capitalizedString];
}
}有没有人能推荐一种更健壮的方法来从字符串中解析出物理地址?我需要能够得到邮政编码,街道,州和城市。
发布于 2014-06-04 10:21:37
NSDataDetector是一个NSRegularExpression子类,所以也许你可以创建一个定制的实例,并从检查苹果把什么作为pattern和options参数开始。
大致是这样的:
NSDataDetector * dataDetectorRegEx = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeAddress error:&error];
NSString * dataDetectorPattern = dataDetectorRegEx.pattern;
NSLog(@"Check out this pattern!: %@", dataDetectorPattern);
// Customize the pattern for your special cases
NSString * customPattern = [NSString stringWithFormat:@"<MY_OTHER_PATERNS + %@>", dataDetectorPattern];
NSRegularExpression * customDataDetectorLikeRegEx = [NSRegularExpression regularExpressionWithPattern:customPattern options:someOptions error:&error];发布于 2014-06-02 08:22:47
您可以尝试使用正则表达式(RegEx)解析地址信息,我认为这是更健壮的方法。请参阅以下使用RegEx的参考:Making RegEx Easy in Objective-C,Objective-C RegEx Categories可在GitHub上找到。
https://stackoverflow.com/questions/23925527
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