我想通过触摸适当的UImageViews来播放几个音频文件(*.wav)。每一次触摸UIImageView都会改变一个“触发器编号”--所选择的视图。音频文件名称存储在一个数组中。但是我不知道如何编写一个方法来获取名称并播放正确的声音,而不使用带有冗余代码片段的select case方法来播放声音:
#pragma mark -
-(void)touchesBegan:(NSSet*)touches withEvent:(UIEvent*)event
{
//Soundfile names in array arrAnimalde
arrAnimalde = [NSArray arrayWithObjects:@"Hund" ,@"Schwein" ,@"Ferkel", nil];
// here are some Views and their triggers
if([touch view] == img_hund){
trigAnimal = 0;
}
if([touch view] == img_schwein){
trigAnimal = 1;
}
if([touch view] == img_ferkel){
trigAnimal = 2;
}
/* here I'd like to have a method to send the triggernumber and get the
soundnameposition in the array to play the appropriate sound e. g. "Hund.wav" which is the first entry
in the array : I tried something with "self.langKeys objectAtIndex:arrAnimalde" instead of the string in the following code but it
does'nt work
*/
//Sound
AudioServicesCreateSystemSoundID ((CFURLRef)[NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource: @"**here please the right name from the array**" ofType: @"wav"]], &soundFileObject);
AudioServicesPlaySystemSound (self.soundFileObject);
}或者这是一个完全错误的解决方法?
相关的第二个问题是:我如何才能把三个“if(触摸视图== img...)”更短的代码(select-case?)声明?
发布于 2010-08-08 05:45:37
试试这个。
[arrAnimalde objectAtIndex: trigAnimal]例如:
AudioServicesCreateSystemSoundID ((CFURLRef)[NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource: [arrAnimalde objectAtIndex: trigAnimal] ofType: @"wav"]], &soundFileObject);https://stackoverflow.com/questions/3432055
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