所以我把这段代码放在一起来ping我的服务器的在线玩家计数/最大玩家数量。我想我已经正确地完成了所有的事情,但是这个错误occurs...any建议如何修复它?下面是错误: Parse error:语法错误,第21行的/home/u7335206/public_html/mc-vr.com/pc.php中意外的'<‘
下面是我的代码:
<?php
require "MinecraftQuery.class.php";
// Variables for each of your servers:
$server_info = array();
try
{
// Getting Server Info:
$query = new MinecraftQuery();
$query->Connect("192.99.14.177", 25573);
$server_info = $query->GetInfo();
}
catch(MinecraftQueryException $e)
{
// Getting the information failed.
}
try
{
<?php if ($server_info) { ?>
<p><span style='font-family: Arial; font-weight: normal; font-style: normal; text-decoration: none;'><font color='#FFFFFF'><?= $server_info["numplayers"] ?>/<?= $server_info["maxplayers"] ?></font></span></p>
<?php } else { ?>
<p><span style='font-family: Arial; font-weight: normal; font-style: normal; text-decoration: none;'><font color='#FFFFFF'>0/120</span></font></p>
<?php } ?>发布于 2014-02-28 09:28:45
变化
try
{
<?php if ($server_info) { ?>至
try
{
if ($server_info) { ?>您还错过了try的结束括号。但是,由于您不是在执行catch(),因此只需删除try
<?php
require "MinecraftQuery.class.php";
// Variables for each of your servers:
$server_info = array();
try
{
// Getting Server Info:
$query = new MinecraftQuery();
$query->Connect("192.99.14.177", 25573);
$server_info = $query->GetInfo();
}
catch(MinecraftQueryException $e)
{
// Getting the information failed.
}
if ($server_info) { ?>
<p><span style='font-family: Arial; font-weight: normal; font-style: normal; text-decoration: none;'><font color='#FFFFFF'><?= $server_info["numplayers"] ?>/<?= $server_info["maxplayers"] ?></font></span></p>
<?php } else { ?>
<p><span style='font-family: Arial; font-weight: normal; font-style: normal; text-decoration: none;'><font color='#FFFFFF'>0/120</span></font></p>
<?php } ?>https://stackoverflow.com/questions/22084326
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