使用re.compile和re.sub

Question

我想从我的文本中删除urls：

#Django url validator https://github.com/django/django/blob/master/django/core/validators.py
regex = re.compile(
    r'^(?:http|ftp)s?://'  # http:// or https://
    r'(?:(?:[A-Z0-9](?:[A-Z0-9-]{0,61}[A-Z0-9])?\.)+(?:[A-Z]{2,6}\.?|[A-Z0-9-]{2,}\.?)|'  # domain...
    r'localhost|'  # localhost...
    r'\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}|'  # ...or ipv4
    r'\[?[A-F0-9]*:[A-F0-9:]+\]?)'  # ...or ipv6
    r'(?::\d+)?'  # optional port
    r'(?:/?|[/?]\S+)$', re.IGNORECASE)
text = "http://test.com word1 word2 https://test.de word3"
text = re.sub(regex, '', text)
print  text

输出仍然是：

http://test.com word1 word2 https://test.de word3

我的代码出了什么问题？

Answer 1

您的正则表达式使用^和$字符锚定在字符串的开头和结尾。所以只要删除它们就行了：

regex = re.compile(
    r'(?:http|ftp)s?://'  # http:// or https://
    r'(?:(?:[A-Z0-9](?:[A-Z0-9-]{0,61}[A-Z0-9])?\.)+(?:[A-Z]{2,6}\.?|[A-Z0-9-]{2,}\.?)|'  # domain...
    r'localhost|'  # localhost...
    r'\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}|'  # ...or ipv4
    r'\[?[A-F0-9]*:[A-F0-9:]+\]?)'  # ...or ipv6
    r'(?::\d+)?'  # optional port
    r'(?:/?|[/?]\S+)', re.IGNORECASE)