我是一个新手,正在试着设置一些基本的桌子。我已经创建了一个名为Customer的表名为Customer,主键为Cust_ID,表名为City,PK为Zip_Code。当我尝试创建一个名为Address的表并将这些PK作为FK包含进来时,我得到了下面的错误。任何帮助都非常感谢,因为已经尝试了几个web解决方案。下面的代码和错误。谢谢,理查德。
CREATE TABLE ADDRESS
( ADDR_ID INTEGER NOT NULL,
Addr_Ln1 VARCHAR2(100) NOT NULL,
Addr_Ln2 VARCHAR2(100) NOT NULL,
CONSTRAINT ADDRESS_PK PRIMARY KEY (ADDR_ID),
CONSTRAINT fk_customer FOREIGN KEY(Cust_ID) REFERENCES CUSTOMER (Cust_ID) ON DELETE CASCADE,
CONSTRAINT fk_city FOREIGN KEY (Zip_Code) REFERENCES CITY (Zip_Code) ON DELETE CASCADE
);这会产生以下错误:
Error starting at line : 1 in command -
CREATE TABLE ADDRESS
( ADDR_ID INTEGER NOT NULL,
Addr_Ln1 VARCHAR2(100) NOT NULL,
Addr_Ln2 VARCHAR2(100) NOT NULL,
CONSTRAINT ADDRESS_PK PRIMARY KEY (ADDR_ID),
CONSTRAINT fk_customer FOREIGN KEY(Cust_ID) REFERENCES CUSTOMER (Cust_ID) ON DELETE CASCADE,
CONSTRAINT fk_city FOREIGN KEY (Zip_Code) REFERENCES CITY (Zip_Code) ON DELETE CASCADE
)
Error at Command Line : 6 Column : 37
Error report -
SQL Error: ORA-00904: "CUST_ID": invalid identifier
00904. 00000 - "%s: invalid identifier"
*Cause:
*Action:发布于 2014-05-04 20:51:26
检查脚本,因为create语句中不存在列"Cust_ID“。您只创建了三个列(ADDR_ID、Addr_Ln1、Addr_Ln2)
https://stackoverflow.com/questions/23455093
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