Grep多字符串搜索-排序输出

Question

以下是我的代码

iwlist wlan0 scan | grep -w "ESSID\|Quality"

它返回

                Quality=53/70  Signal level=-57 dBm
                ESSID:"NETGEAR00"
                Quality=50/70  Signal level=-60 dBm
                ESSID:"dlink_test"
                Quality=56/70  Signal level=-54 dBm
                ESSID:""
                Quality=49/70  Signal level=-61 dBm
                ESSID:"linksys"
                Quality=67/70  Signal level=-43 dBm

我想先按ESSID排序，然后在同一行上按质量级别排序。

ESSID:"NETGEAR00"                  Quality=53/70  Signal level=-57 dBm

有什么建议吗？Linux Newb！

Answer 1

看起来您并不想排序，而是简单地连接成对的行(第一行之前的第二行)。尝试：

iwlist wlan0 scan | grep -w "ESSID\|Quality" | tac | sed '$!N;s/\n/\t/'

对于给定的输入，它将生成：

ESSID:"linksys" Quality=49/70  Signal level=-61 dBm
ESSID:""    Quality=56/70  Signal level=-54 dBm
ESSID:"dlink_test"  Quality=50/70  Signal level=-60 dBm
ESSID:"NETGEAR00"   Quality=53/70  Signal level=-57 dBm