我正在寻找三列中最小的一列(Market, LiFo, Wgtd_Avg)。我可以这样做,但不包括等于零的三个值中的任何一个。
我只想找到那些> zero中最小的一个。
SELECT Market, LiFo, Wgtd_Avg,
(
CASE
WHEN Market < LiFo AND Market < Wgtd_Avg AND Market > 0 THEN Market
WHEN LiFo < Wgtd_Avg AND LiFo > 0 THEN LiFo
WHEN Wgtd_Avg > 0 THEN Wgtd_Avg
ELSE 0
END
) AS LeastOfThree
FROM VF_CasINV_Cost发布于 2011-06-30 19:41:54
原始答案:
SELECT min(Value) FROM
(
SELECT Market as Value FROM VF_CasINV_Cost WHERE Market > 0
UNION
SELECT Wgtd_Avg as Value FROM VF_CasINV_Cost WHERE Wgtd_Avg > 0
UNION
SELECT LiFo as Value FROM VF_CasINV_Cost WHERE LiFo > 0
) union_table评论后编辑:
SELECT Market, Wgtd_Avg, LiFo, min(least) AS leastOfThree FROM
(
SELECT min(market) as market, min(Market) as least FROM VF_CasINV_Cost WHERE Market > 0
UNION
SELECT min(Wgtd_avg) as Wgtd_Avg, min(Wgtd_Avg) as least FROM VF_CasINV_Cost WHERE Wgtd_Avg > 0
UNION
SELECT min(lifo) as LiFo, min(lifo) as least FROM VF_CasINV_Cost WHERE LiFo > 0
) as union_table我离开了一台装有sql服务器的计算机,所以现在不能测试它,但它应该已经接近工作了……我一回来就对它进行测试和编辑。
发布于 2011-07-01 13:56:49
SELECT
MIN(
CASE x.f
WHEN 1 THEN t.Market
WHEN 2 THEN t.Wgtd_Avg
WHEN 3 THEN t.LiFo
END
) AS MinValue
FROM VF_Cas_INV_Cost t
INNER JOIN (SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3) x (f)
ON CASE x.f
WHEN 1 THEN t.Market
WHEN 2 THEN t.Wgtd_Avg
WHEN 3 THEN t.LiFo
END > 0https://stackoverflow.com/questions/6534131
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