选择选项update db from linking

Question

如何从select选项更新数据库。

如果选择了test，则从db行更新用户id。

<form action="action.php?id=<?php echo $dnn['id'] ?>" method="post">
<select name="op">
<option value="test">test</option>
<option value="test2">test2</option>
</select>
<input name="submit" type="submit" value="submit" />
</form>
<?php
if (isset($_POST['submit']))
{
if ($_POST['op'] == "test") 
{ 
$sql = "UPDATE * from users SET increment = increment + 1 WHERE id = '".$id."'";
mysql_query($sql); 
}
else 
{ 
echo "test2 is selected can't update the db"; 
}
}
?>

Answer 1

从了解MySQL基础知识。

和改变：

$sql = "UPDATE * from users SET increment = increment + 1 WHERE id = '".$id."'";

至

$sql = "UPDATE users SET increment = increment + 1 WHERE id = '".$id."'";

Answer 2

我认为您正在讨论通过get方法从操作属性中检索主键id。将您的查询更新为

$sql = "UPDATE users SET increment = increment + 1 WHERE id = '".$_REQUEST['id']."'";