安卓:如何改变ShapeDrawable的背景

Question

我在下面的代码中遇到了问题。

我想创建一个戏剧性的层级列表。如果我用setColor(int color)设置每一层的背景，它会给我一个很好的结果。但是现在我想用drawable来设置背景。但是结果并不是我所期望的。

public LayerDrawable testCreate() {

    ShapeDrawable background = new ShapeDrawable();

    background.getPaint().setStyle(Style.FILL);
    background.getPaint().setColor(R.drawable.progress_background);
            // if using setColor(
    //   getResources().getColor(android.R.color.background_dark)); result will        //be ok



    ShapeDrawable shapeD = new ShapeDrawable();
    shapeD.getPaint().setStyle(Style.FILL);
    shapeD.getPaint().setColor(R.drawable.progress_progress);
    ClipDrawable clipDrawable = new ClipDrawable(shapeD, Gravity.LEFT,
        ClipDrawable.HORIZONTAL);

    LayerDrawable layerDrawable = new LayerDrawable(new Drawable[] {
        clipDrawable, background });
    return layerDrawable;

}

Answer 1

使用以下函数创建BitmapDrawable

private BitmapDrawable getDrawable(Resources r, int rId) {
    Bitmap image = BitmapFactory.decodeResource(r, rId);
            //to set height and width call this
    //Bitmap.createScaledBitmap(image, height, width, false);
    return new BitmapDrawable(r, image);
}

并将您的函数更改为：

public LayerDrawable testCreate() {

    Drawable background = getDrawable(getResources(),R.drawable.progress_background);

            // if using setColor(android.R.color.background_dark), result will be ok



    Drawable shapeD = getDrawable(getResources(),R.drawable.progress_progress);

    ClipDrawable clipDrawable = new ClipDrawable(shapeD, Gravity.LEFT,
        ClipDrawable.HORIZONTAL);

    LayerDrawable layerDrawable = new LayerDrawable(new Drawable[] {
        clipDrawable, background });
    return layerDrawable;

}

Answer 2

使用可绘制的数字资源id调用setColor(__int color)。