我是PL/SQL语言的新手,我正在解决一个问题,并在寻找正确方向的建议。任何帮助都将不胜感激!
我有一个Employee表和一个Building表。
Employee表包括Employee_ID、Last_Name、First_Name和职务(F/P)(全职或兼职)。建筑物表由Employee_ID和Building_location组成。(这是员工工作的位置)家庭或办公室。
我想让用户输入用户输入的last_name。因此,我要从Employee中查找信息:employee Name、Job (full or部分employee)和building_location。例如,如果用户键入Johnson,我希望我的输出如下所示:
Employee Name Job Position Building Location
====================================================
Andre Johnson Part Time Home Office
Nick Johnson Full Time Downtown Office如果用户输入任何字符串,我希望列出为该公司工作的所有员工。但是,如果姓名在Employee表中,如' Johnson‘is,则只显示Johnson。我需要添加另一个SELECT子句吗?
在这一点上,我整理了一些代码来检查员工是否为公司工作。我希望在此基础上建立。
ACCEPT p_1 PROMPT 'Please enter the last name of the employee:'
DECLARE
v_name employee.last_name%TYPE := '&p_1';
v_lname employee.last_name%TYPE;
v_fname employee.first_name%TYPE;
v_jobpos employee.job%TYPE;
v_buildtype building.building_type%TYPE;
v_count NUMBER;
BEGIN
SELECT COUNT(*)
INTO v_count
FROM employee
WHERE UPPER(last_name) = UPPER(v_name);
IF v_count = 0 THEN
DBMS_OUTPUT.PUT_LINE('EMPLOYEE NAME Job Position Building Location');
DBMS_OUTPUT.PUT_LINE('----------------------------------------------------' );
for i in (select * from employee order by last_name) loop
DBMS_OUTPUT.PUT_LINE(i.last_name || ', ' || i.first_name)
end loop;
ELSE
for i in (select * from employee order by last_name) loop
DBMS_OUTPUT.PUT_LINE(i.last_name || ', ' || i.first_name);
end loop;
END IF;
END;发布于 2013-05-09 23:13:05
你可以做到这一点。最简单的方法可能是这样:
...
IF v_count = 0 THEN
DBMS_OUTPUT.PUT_LINE(v_name || ' Does not work here.');
/* New code starts here! */
DBMS_OUTPUT.PUT_LINE('Employees are:');
for r in (select * from employees) loop
dbms_output.put_line(r.last_name||', '||r.first_name);
end loop;
/* New code ends here! */
ELSE
...
end if;
end;https://stackoverflow.com/questions/16465007
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