Inform7:如何在inform7中的特定情况下创建随机事件？

Question

我想在我的Inform7游戏中实现一个功能：

当玩家决定向北通过人行横道时，第一次解说员将向玩家表明玩家有可能死亡，如果玩家再次键入向北，则事件将发生，并且在1/2成功的随机机会中，玩家将能够前往花园。如下所示：

        Instead of going north in the road for the second time when a random chance of 1 in 2 succeeds:
        say "Yay! You made it!";
        now the player is in the Garden.

        otherwise:
        say "The car crashed you instantly - without any hope, you lost your whole strength in your body…";
        end the game in death.

是的，这个代码不能工作..有没有人能帮我弄清楚怎么做？

Answer 1

这段代码有两个问题：

1. Inform不允许在for the second time之后使用when子句。(你可以写成相反的方式，比如“当2中有1的随机机会第二次成功时”，但这意味着不同的意思:它将在第二次随机机会成功时触发规则，也就是说，玩家第二次通过road.)
2. otherwise幸存时必须是if语句的一部分；它不能与when子句一起使用。

要修复代码，您只需将“随机机会”条件移动到if语句中，然后更改标点符号，以便两个备选方案都属于同一规则：

[I added these lines to make a complete example...]
Road is a room.

Garden is a room, north of Road.

Instead of going north in the road for the first time:
    say "The road looks dangerous. You hesitate a moment, unsure if you really want to take the risk."

[And here's the fixed rule:]
Instead of going north in the road for the second time:
    if a random chance of 1 in 2 succeeds:
        say "Yay! You made it!";
        now the player is in the Garden;
    otherwise:
        say "The car crashed you instantly - without any hope, you lost your whole strength in your body…";
        end the game in death.