Sapi动态语法加载

Question

我有一个sapi文法作为

<rule id="root">
    <item repeat="0-">
       <ruleref uri="#digit"></ruleref>
     </item>
 </rule>

<rule id="digit">
<one-of>
      <item>1</item>
      <item>2</item>
      <item>3</item>
      <item>4</item>
      <item>5</item>
      <item>6</item>
      <item>7</item>
      <item>8</item>
      <item>9</item>
      <item>0</item>
  </one-of>
 </rule>

我想要动态加载语法的等价物，有人能帮我吗？

我试过了

SPSTATEHANDLE hRule;
hr = cpGrammar->GetRule(L"digit", NULL, SPRAF_TopLevel | SPRAF_Active, TRUE,&hRule);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"1", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"2", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"3", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"4", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"5", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"6", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"7", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"8", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"9", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"0", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->Commit(NULL);
hr = cpGrammar->SetGrammarState(SPGS_ENABLED);

这对我不起作用，我做的是对的吗？

Answer 1

回顾了一些构建动态语法的代码，我非常确定您需要使用SPRAF_Dynamic和SPRAF_TopLevel | SPRAF_Active。(至少，我编写的代码使用了这一点。)