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Google Maps Store Locator PHP/MySQL
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Stack Overflow用户
提问于 2014-03-13 22:14:28
回答 1查看 3.9K关注 0票数 0

我正在尝试遵循这个教程:

https://developers.google.com/maps/articles/phpsqlsearch_v3

不幸的是,我在XML输出中总是得到空值:

代码语言:javascript
复制
<Competitors>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
    <Competitors Name="" Address="" lat="" lng="" Distance="0"/>
</Competitors>

我已经在我的数据库中设置了一个类似于本教程中所示的表:

根据本教程,下面是我生成XML的代码:

代码语言:javascript
复制
<?php  
$username="#######";
$password="#######";
$database="#######";

// Get parameters from URL
$center_lat = $_GET["lat"];
$center_lng = $_GET["lng"];
$radius = $_GET["radius"];

// Start XML file, create parent node
$dom = new DOMDocument("1.0");
$node = $dom->createElement("Competitors");
$parnode = $dom->appendChild($node);

// Opens a connection to a mySQL server
$connection=mysql_connect ("host", $username, $password);
if (!$connection) {
  die("Not connected : " . mysql_error());
}

// Set the active mySQL database
$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
  die ("Can\'t use db : " . mysql_error());
}

// Search the rows in the Competitors table
$query = sprintf("SELECT 'Address', 'Name', 'Lat', 'Lng', 
( 3959 * acos( cos( radians('%s') ) * cos( radians( 'Lat' ) ) * cos( radians( 'lng' ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( 'Lat' ) ) ) ) AS distance 
FROM Competitors 
HAVING distance < '%s' 
ORDER BY distance LIMIT 0 , 20",
  mysql_real_escape_string($center_lat),
  mysql_real_escape_string($center_lng),
  mysql_real_escape_string($center_lat),
  mysql_real_escape_string($radius));
$result = mysql_query($query);

if (!$result) {
  die("Invalid query: " . mysql_error());
}

header("Content-type: text/xml");

// Iterate through the rows, adding XML nodes for each
while ($row = @mysql_fetch_assoc($result)){
  $node = $dom->createElement("Competitors");
  $newnode = $parnode->appendChild($node);
  $newnode->setAttribute("Name", $row['name']);
  $newnode->setAttribute("Address", $row['address']);
  $newnode->setAttribute("lat", $row['lat']);
  $newnode->setAttribute("lng", $row['lng']);
  $newnode->setAttribute("Distance", $row['distance']);
}

echo $dom->saveXML();
?>

我不确定我在哪里犯了错--任何帮助都将不胜感激!

EN

回答 1

Stack Overflow用户

发布于 2014-03-13 22:44:02

你需要换掉这个

代码语言:javascript
复制
// Opens a connection to a mySQL server
$connection=mysql_connect ('host', $username, $password);
if (!$connection) {
  die("Not connected : " . mysql_error());
}

使用

代码语言:javascript
复制
// Opens a connection to a mySQL server
$connection=mysql_connect ('localhost', $username, $password);
if (!$connection) {
  die("Not connected : " . mysql_error());
}

我刚试过,我得到了xml

此外,代码示例只使用了localhost而不是"localhost",因此php认为它是一个常量

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/22381315

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