请帮帮我。
我已经在我的主活动中设置了一个弹出窗口,当我按下第一个按钮时。它工作得很好,我可以通过我设置的关闭按钮关闭它,如果我想触摸外部的话也可以。
但我需要在同一个活动中有多个弹出窗口。我有各种各样的按钮,如果你按下它们,他们应该会通过弹出窗口给你更多信息。现在我已经创建了我的第二个按钮,当我打开弹出窗口时,它就可以工作了。
这是问题所在。当我现在关闭它时,我必须在弹出窗口外按两次,或在弹出窗口外按一次,然后按关闭按钮。只有这样,我才会返回到我的菜单屏幕。所以我按下这两个按钮中的哪一个并不重要,这两个按钮都会打开两个弹出窗口。这真的很烦人,我希望有比我更聪明的人能帮助我。
这是我的menu.java
package com.fadi.enumbers;
import android.app.Activity;
import android.content.Context;
import android.content.res.Resources;
import android.graphics.Bitmap;
import android.graphics.drawable.BitmapDrawable;
import android.os.Bundle;
import android.view.Gravity;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.PopupWindow;
public class menu extends Activity {
Button btnClosePopup;
Button btnCreatePopup;
Button btnCreatePopup2;
Bitmap bitmap;
Resources res;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
btnCreatePopup = (Button) findViewById(R.id.btn_e100);
btnCreatePopup2 = (Button) findViewById(R.id.btn_e100ii);
btnCreatePopup.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
initiatePopupWindow();
}
});
btnCreatePopup2.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
initiatePopupWindow();
}
});
}
private PopupWindow pwindo;
private PopupWindow pwindo2;
private void initiatePopupWindow() {
try {
// We need to get the instance of the LayoutInflater
LayoutInflater inflater = (LayoutInflater) menu.this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View layout = inflater.inflate(R.layout.screen_popup,(ViewGroup) findViewById(R.id.popup_element));
pwindo = new PopupWindow(layout, 370, 450, true);
pwindo.setBackgroundDrawable(new BitmapDrawable(res, bitmap));
pwindo.showAtLocation(layout, Gravity.CENTER, 0, 0);
btnClosePopup = (Button) layout.findViewById(R.id.btn_close_popup);
btnClosePopup.setOnClickListener(cancel_button_click_listener);
} catch (Exception e) {
e.printStackTrace();
}
try {
// We need to get the instance of the LayoutInflater
LayoutInflater inflater = (LayoutInflater) menu.this .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View layout2 = inflater.inflate(R.layout.screen_popup2, (ViewGroup)findViewById(R.id.popup_element));
pwindo2 = new PopupWindow(layout2, 370, 450, true);
pwindo2.setBackgroundDrawable(new BitmapDrawable(res, bitmap));
pwindo2.showAtLocation(layout2, Gravity.CENTER, 0, 0);
btnClosePopup = (Button) layout2.findViewById(R.id.btn_close_popup);
btnClosePopup.setOnClickListener(cancel_button_click_listener);
} catch (Exception e) {
e.printStackTrace();
}
}
private OnClickListener cancel_button_click_listener = new OnClickListener() {
public void onClick(View v) {
pwindo.dismiss();
}
};
}发布于 2014-03-12 14:36:57
在您的initiatePopupWindow()中,您正在创建两个弹出对话框。这就是为什么它会那样做的原因。
做一些事情,比如传递一个int值,以区分调用initiatePopupWindow()方法的按钮,如下所示
btnCreatePopup.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
initiatePopupWindow(1);
}
});
btnCreatePopup2.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
initiatePopupWindow(2);
}
});然后
private void initiatePopupWindow(int popupNo) {
swich(popupNo)
{
case 1:
try {
// We need to get the instance of the LayoutInflater
LayoutInflater inflater = (LayoutInflater) menu.this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View layout = inflater.inflate(R.layout.screen_popup,(ViewGroup) findViewById(R.id.popup_element));
pwindo = new PopupWindow(layout, 370, 450, true);
pwindo.setBackgroundDrawable(new BitmapDrawable(res, bitmap));
pwindo.showAtLocation(layout, Gravity.CENTER, 0, 0);
btnClosePopup = (Button) layout.findViewById(R.id.btn_close_popup);
btnClosePopup.setOnClickListener(cancel_button_click_listener);
} catch (Exception e) {
e.printStackTrace();
}
break;
case 2:
try {
// We need to get the instance of the LayoutInflater
LayoutInflater inflater = (LayoutInflater) menu.this .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View layout2 = inflater.inflate(R.layout.screen_popup2, (ViewGroup)findViewById(R.id.popup_element));
pwindo2 = new PopupWindow(layout2, 370, 450, true);
pwindo2.setBackgroundDrawable(new BitmapDrawable(res, bitmap));
pwindo2.showAtLocation(layout2, Gravity.CENTER, 0, 0);
btnClosePopup = (Button) layout2.findViewById(R.id.btn_close_popup);
btnClosePopup.setOnClickListener(cancel_button_click_listener);
} catch (Exception e) {
e.printStackTrace();
}
break;
}为这两个按钮使用单独取消侦听器是对侦听器进行自定义,以便为这两个对话框工作。
https://stackoverflow.com/questions/22338800
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