我想知道是否有人熟悉用于排序和获取差异表达基因的Bioconductor RankProduct软件包。有关该软件的一些信息如下:paper、manual、documentation。
我在使用这个程序时遇到了一些问题,可能是因为我对R语言知之甚少。我尝试用我自己的数据复制上面的pdf文件中的步骤。虽然我自己的数据集并不在示例中所示的afffy .cel文件中,但只是作为制表符分隔文件中的行和列。我有两个条件(1和2,replicate =4)
下面是我的代码:
library(RankProd)
library(preprocessCore)
#Read expression data
#gdata <- read.table(file="data2.txt", sep="\t", header=T) #9000 rows of genes X 8 columns of chips
gdata <- read.table(file="data2.txt", sep="\t", header=T, row.names=1) #9000 rows of genes X 8 columns of chips
#colnames(gdata)
# This vector contains the microarray sample names
SampleNames= names(data.frame(gdata[,-1]))
#names(datExpr)=gdata[,1]
# This vector contains the gene names
datExpr.gnames= gdata$GeneName
# Since the first column contains the gene names, exclude it.
# dataExp is then the matix required
datExpr=data.frame(gdata[,-1])
#convert data into matrix form
datExpr <- as.matrix(datExpr)
#data normalization - quantile normalization
#datExpr.log.norm <- normalize.quantiles((log2(datExpr)),copy=TRUE) #with logged data
datExpr <- datExpr.log.norm
#datExpr.norm <- normalize.quantiles(datExpr,copy=TRUE) #without logged data
#datExpr <- datExpr.norm
# Identify two class data - control/treatment (or condition 1/condition2)
nl <- 4
n2 <- 4
cl <- rep(c(0,1), c(nl, n2))
datExpr.cl <- cl
# data were generated under identical or very similar conditions except the
# factor of interest (e.g., control and treatment),
origin <- rep(1, nl + n2)
datExpr.origin <- origin
# Data anslysis
datExpr.sub <- datExpr[,which(datExpr.origin == 1)]
datExpr.cl.sub <- datExpr.cl[which(datExpr.origin == 1)]
datExpr.origin.sub <- datExpr.origin[which(datExpr.origin == 1)]
#Rank product analysis and output
#RP.out <- RP(datExpr.sub, datExpr.cl.sub, num.perm = 100, logged = TRUE,na.rm = FALSE, plot = FALSE, rand = 123)
RP.out <- RPadvance(datExpr.sub, datExpr.cl.sub, datExpr.origin.sub, num.perm = 100,logged = TRUE,
na.rm = FALSE, gene.names = datExpr.gnames, plot = FALSE,rand = 123)
# Output a table of the identified genes based on user-specified selection criteria
topGene(RP.out, cutoff = 0.05, method = "pfp", logged = TRUE,logbase = 2, gene.names = datExpr.gnames)我确实运行了代码,但我在一种情况下对差异表达基因的折叠变化要么是0,要么是无穷大。我想知道有没有对这个项目有经验的人能帮我。
发布于 2013-02-14 16:40:09
乍一看,我注意到的是
#datExpr.log.norm <- normalize.quantiles((log2(datExpr)),copy=TRUE) #with logged data
datExpr <- datExpr.log.norm在这里,只要第一行被注释掉,datExpr结果就会为空。
https://stackoverflow.com/questions/14868462
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