cakePHP 1.3 :使用Ajax渲染问题

Question

我希望在我的ajax响应中包含一个字符串形式的元素。

因此，我将以下代码放入了我的控制器操作中

$view = new View($this, false);
$view->viewPath = 'elements/private_challenge/';            
$res = $view->render('supporters_list_supporter');

现在，在我的supporters_list_supporter.ctp中，我放置了一个表单，如下所示：

echo $this->Form->create('RequestFrHelpReply',array('action'=>'add_helpreq_reply','class'=>'form','id' => 'helprequestreplyaddfrm','name'=>'helprequestreplyaddfrm')); 

 echo $this->Form->hidden('PrivateChallengeRequestHelp.ReqID',array('value'=>$supporterlist['RequestFrHelp']['REQID']));
 echo "<div class='alignleft'>";
 echo $this->Form->input('PrivateChallengeRequestHelp.txt_helpreq_reply', array('label'=>false,'type' => 'textarea', 'id'=>'txt_helpreq_reply','escape' => false, 'div' => false, "class"=>"textarea request-help-textarea",'onKeyDown'=>'textCounterComment(this.form.txt_helpreq_reply,this.form.remLenth,'.Configure::read('CommentSetting.comment_body_max_limit').',\'remLenthDiv\');', 'onKeyUp'=>'textCounterComment(this.form.txt_helpreq_reply,this.form.remLenth,'.Configure::read('CommentSetting.comment_body_max_limit').',\'remLenthDiv\');'));
  echo "</div>";
  echo '<span class="request-arrow"></span><span class="user-name"> : '.$html->get_users_username($session->read('Auth.User.id')).'</span>';
 echo $html->link(__l('Reply'),'#',array('id'=>'helpreq_reply_link','class'=>'request-help-button alignleft','title'=>__l('Reply'),'escape'=>false,'onclick'=>'helpreq_reply(\'reply\');return false;'));               
 echo "</div>";     
 echo $this->Form->end();

所以它给了我一个与表单助手丢失相关的错误，所以有人能帮我添加这个外部对象的表单助手吗？

更新:错误消息：

   $view = stdClass
   stdClass::$modelScope = false
   stdClass::$entityPath = "RequestFrHelpReply."</pre><pre class="stack-trace">Helper::setEntity() - CORE\cake\libs\view\helper.php, line 422
   FormHelper::create() - CORE\cake\libs\view\helpers\form.php, line 217
   include - APP\views\elements\private_challenge\help_request_form.ctp, line 21

Answer 1

你有没有

public $helpers = array('Form');

在你的控制器里？