使用Soundex、python替换单词

Question

我有一个句子列表，基本上我的目标是将所有不同的介词形式"opp，nr，off，abv，behnd“替换为正确的拼写”对立面，近处，上方，后面“等等。单词的soundex代码是相同的，所以我需要构建一个表达式来逐个单词地迭代这个列表，如果soundex是相同的，就用正确的拼写替换它。

一个例子-[‘杰克站在树上’，

     'they were abv everything he planned' ,

 'Just stand opp the counter' ,

 'Go twrds the gas station']

所以我需要用正确的完整形式替换单词nr，abv，opp和twrds。方向和twrds的soundex代码是相同的，所以应该替换它。

我需要遍历这个列表。

以下是soundex算法：

import string

allChar = string.uppercase + string.lowercase
charToSoundex = string.maketrans(allChar, "91239129922455912623919292" * 2)

def soundex(source):
    "convert string to Soundex equivalent"

    # Soundex requirements:
    # source string must be at least 1 character
    # and must consist entirely of letters
    if (not source) or (not source.isalpha()):
    return "0000"

    # Soundex algorithm:
    # 1. make first character uppercase
    # 2. translate all other characters to Soundex digits
    digits = source[0].upper() + source[1:].translate(charToSoundex)

    # 3. remove consecutive duplicates
    digits2 = digits[0]
    for d in digits[1:]:
        if digits2[-1] != d:
           digits2 += d

    # 4. remove all "9"s
    # 5. pad end with "0"s to 4 characters
    return (digits2.replace('9', '') + '000')[:4]

if __name__ == '__main__':
   import sys
   if sys.argv[1:]:
      print soundex(sys.argv[1])
   else:
    from timeit import Timer
    names = ('Woo', 'Pilgrim', 'Flingjingwaller')
    for name in names:
        statement = "soundex('%s')" % name
        t = Timer(statement, "from __main__ import soundex")
        print name.ljust(15), soundex(name), min(t.repeat())

我是一个新手，所以如果你有其他的建议，我将不胜感激。谢谢。

Answer 1

我将使用enchant模块：

import enchant
d = enchant.Dict("en_US")

phrase = ['Jack was standing nr the tree' ,
'they were abv everything he planned' ,
'Just stand opp the counter' ,
'Go twrds the gas station']

output = []
for section in phrase:
    sect = ''
    for word in section.split():
        if d.check(word):
            sect += word + ' '
        else:
            for correct_word in d.suggest(word):
                if soundex(correct_word) == soundex(word):
                    sect +=  correct_word + ' '
    output.append(sect[:-1])