Google混合( openid + oauth)协议不适用于127.0.0.1

Question

我正在尝试实现google混合协议(oauth over openid)。还有一个问题是，谷歌没有请求oauth许可(尝试使用gmail)，只请求openid。我在google api控制台注册：

Client ID for web applications
Client ID: 248141267047.apps.googleusercontent.com
Email address:248141267047@developer.gserviceaccount.com
Client secret: 
Redirect URIs:  http://127.0.0.1:8000/oauth2callback
JavaScript origins:     http://127.0.0.1:8000

下面是我用来生成openid url的python代码：

class OpenIDOAuthRequest(Extension):

    ns_alias = 'oauth'

    def __init__(self, consumer, scope, ns_uri=None):
        Extension.__init__(self)
        self.consumer = consumer
        self.scope = scope
        self.ns_uri = ns_uri or oauth_ns_uri

    def getExtensionArgs(self):
        return {
            'consumer': self.consumer,
            'scope': ' '.join(self.scope),
        }


def google():
        #define google openid url
        openid_session = {}
        openid_store = filestore.FileOpenIDStore('.')
        consumer = Consumer(openid_session, openid_store)
        openid = u"https://www.google.com/accounts/o8/id"
        URLS = {
            'ax_last': "http://axschema.org/namePerson/last",
            'ax_first': "http://axschema.org/namePerson/first",
            'ax_email': "http://axschema.org/contact/email",
            "country":"http://axschema.org/contact/country/home",
            "timezone":"http://axschema.org/pref/timezone",
            "language":"http://axschema.org/pref/language",
            "person":"http://axschema.org/namePerson",
        }
        #defining what fields we're going to get
        ax_request = ax.FetchRequest()
        for k,v in URLS.iteritems():
            ax_request.add(ax.AttrInfo(v, required = True))
        oa = OpenIDOAuthRequest("248141267047.apps.googleusercontent.com",["https://mail.google.com/",])
        try:
            authrequest = consumer.begin(openid)
        except DiscoveryFailure, e:
            print e
            print "some errror happened"
        else:
            authrequest.addExtension(ax_request)
            authrequest.addExtension(oa)



        redirecturl = authrequest.redirectURL("http://127.0.0.1:8000",
            return_to = "http://127.0.0.1:8000/oauth2callback",
            immediate=False)
        print redirecturl

它会生成以下url：

https://accounts.google.com/o/openid2/auth?openid.assoc_handle=AMlYA9Vr6Biwp-rCAr4TLbf8CtItR-zr3bs0LT7oYQ3Pakg93ivCS_6C&openid.ax.mode=fetch_request&openid.ax.required=ext0,ext1,ext2,ext3,ext4,ext5,ext6&openid.ax.type.ext0=http://axschema.org/contact/email&openid.ax.type.ext1=http://axschema.org/namePerson&openid.ax.type.ext2=http://axschema.org/namePerson/first&openid.ax.type.ext3=http://axschema.org/pref/timezone&openid.ax.type.ext4=http://axschema.org/pref/language&openid.ax.type.ext5=http://axschema.org/contact/country/home&openid.ax.type.ext6=http://axschema.org/namePerson/last&openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select&openid.identity=http://specs.openid.net/auth/2.0/identifier_select&openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0&openid.ns.ax=http://openid.net/srv/ax/1.0&openid.ns.oauth=http://specs.openid.net/extensions/oauth/1.0&openid.oauth.consumer=248141267047.apps.googleusercontent.com&openid.oauth.scope=https://mail.google.com/&openid.realm=http://127.0.0.1:8000&openid.return_to=http://127.0.0.1:8000/oauth2callback?janrain_nonce%3D2012-05-01T22%253A50%253A33ZUW7vcj

而且它有所有必要的扩展。但是如果我转到这个url，它不会要求我允许使用gmail。此外，我还比较了来自sanebox.com的类似网址。在请求gmail许可的情况下，它可以像预期的那样工作。但是我看不出他们的url和我的url有什么本质上的区别。此外，我将我的url中的127.0.0.1替换为sanebox，并保留其他部分不变。还有..。现在，它正在申请gmail的许可。切换回127.0.0.1 -停止询问。这是sanebox的url：

https://accounts.google.com/o/openid2/auth?openid.assoc_handle=AMlYA9UV4Ud714HHaFJ0fpItabA8v-zw0QuReEPcn61ilJzyFrFia5PO&openid.ax.mode=fetch_request&openid.ax.required=ext0,ext1,ext2,ext3,ext4,ext5,ext6&openid.ax.type.ext0=http://axschema.org/pref/timezone&openid.ax.type.ext1=http://axschema.org/contact/country/home&openid.ax.type.ext2=http://axschema.org/pref/language&openid.ax.type.ext3=http://axschema.org/namePerson/last&openid.ax.type.ext4=http://axschema.org/namePerson/first&openid.ax.type.ext5=http://axschema.org/namePerson&openid.ax.type.ext6=http://axschema.org/contact/email&openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select&openid.identity=http://specs.openid.net/auth/2.0/identifier_select&openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0&openid.ns.ax=http://openid.net/srv/ax/1.0&openid.ns.oauth=http://specs.openid.net/extensions/oauth/1.0&openid.ns.sreg=http://openid.net/extensions/sreg/1.1&openid.oauth.consumer=www.sanebox.com&openid.oauth.scope=https://mail.google.com/+http://www.google.com/m8/feeds&openid.realm=https://www.sanebox.com/&openid.return_to=https://www.sanebox.com/users?_method%3Dpost%26open_id_complete%3D1

那么我错过了什么呢？如果我在api控制台重新设置了这个url，为什么它不适用于127.0.0.1。它在openid上工作得很好。在没有openid的情况下，可以很好地与oauth本身一起工作。但是现在，当我尝试在openid上使用oauth时，它不会要求我允许我访问gmail。

Answer 1

我已经运行了PHP、ASP、DOT NET代码，它们运行得非常好，因此确保python应用程序也能正确运行。您必须更改默认应用程序。首先运行他们提供的默认应用程序，并尝试更改。如果有默认的应用程序不工作，那么to也可以打开一个bug报告给google。