AJAX ModalPopup不显示
AJAX ModalPopup不显示
提问于 2013-12-18 04:20:03
我似乎无法显示Modal弹出窗口。使用下面的代码，显示器变得模糊，但没有窗口显示。
<%@ Register Assembly="AjaxControlToolkit" Namespace="AjaxControlToolkit" TagPrefix="AjaxToolkit" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:Button ID="btnShow" runat="server" Text="Open ModalPopup" OnClientClick="return ShowModalPopup('modal');" />
<ajaxToolkit:ModalPopupExtender runat="server" ID="modal" BackgroundCssClass="darken"
CancelControlID="btnCancel" PopupControlID="pnl" TargetControlID="btnShow" />
<asp:Panel ID="pnl" runat="server" style="width:55%;display:none;">
<h1>You can now see me!</h1>
<p>"Lorem ipsum dolor sit amet, consectetur adipisicing elit,
sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.
Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris
nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in
reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla
pariatur. Excepteur sint occaecat cupidatat non proident, sunt in
culpa qui officia deserunt mollit anim id est laborum."</p>
<asp:Button ID="btnCancel" runat="server" Text="Close" />
</asp:Panel>
<asp:ScriptManager ID="ScriptManager1" runat="server"/>
</div>
</form>
</body>
</html>
<script type="text/javascript">
function ShowModalPop(PopupExtenderID) {
var ModalPopWindowShow = $find(PopupExtenderID);
if (ModalPopWindowShow) {
ModalPopWindowShow.show();
}
return false;
}
</script>代码隐藏：
protected void Page_Load(object sender, EventArgs e)
{
_grid.DataSource = BuildList();
_grid.DataBind();
}
private List<EntityPerson> BuildList()
{
...
}
protected override void OnInit(EventArgs e)
{
base.OnInit(e);
btnShow.Click +=new EventHandler(btnShow_Click);
}
protected void btnShow_Click(object sender, EventArgs e)
{
Button btnShow = sender as Button;
ScriptManager.RegisterStartupScript(btnShow, btnShow.GetType(), "Popup", "return ShowModalPopup('modal');", true);
}非常感谢您的帮助。如果有另外一种用AJAX显示弹出窗口的方法，我也会很感激。我只需要能够在用户单击网格中的单元格时在模式窗口中显示单元格内容。
回答 1
Stack Overflow用户
发布于 2013-12-19 02:28:37
我换掉了
<asp:ScriptManager ID="ScriptManager1" runat="server"/>使用
<ajaxToolkit:ToolkitScriptManager ID="ajaxSM" runat="server" />我把弹出窗口展示出来了。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/20643869
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