python-fu选择复制粘贴

Question

我是python-fu的新手(第二天)，所以我的问题可能看起来很天真:我想从"r400r.png“中选择一个矩形部分，将其旋转90度，然后将选择保存在"r400ra.png”中。

到目前为止，我在这些代码行上尝试了一些东西：

for fv in range(400,401):
  fn='r%sr.png' % fv
  img=pdb.gimp_file_load('/path/'+fn,fn)
  drw=pdb.gimp_image_get_active_layer(img)
  img1=pdb.gimp_image_new(1024,1568,0)
  lyr=pdb.gimp_layer_new(img1,1024,1568,0,'ly1',0,0)

  pdb.gimp_rect_select(img,10,200,1422,1024,2,0,0)
  drw=pdb.gimp_rotate(drw,0,1.570796327)
  pdb.script_fu_selection_to_image(img1,drw)
  f0=fn[:5]+'a'+fn[5:]
  pdb.gimp_file_save(drw,'/path/'+f0,f0)

"lyr“层在那里是因为我的理解是它是必须的，尽管我不清楚为什么。" for“循环最终应该批量处理一堆文件；为了进行测试，它仅限于一个文件。当我尝试执行"script_fu_selection_to_image“时，我得到一个错误。

你能给我指个方向吗？

谢谢，SxN

Answer 1

执行此操作的PDB调用按以下顺序更好：

# import your image:
img=pdb.gimp_file_load('/path/'+fn,fn)

#make the selection
pdb.gimp_rect_select(img,10,200,1422,1024,2,0,0)


# copy
pdb.gimp_edit_copy(img.layers[0])
# (no need to "get_active_layer" - if
# your image is a flat PNG or JPG, it only has one layer,
# which is accessible as img.layers[0]) 

# create a new image from the copied area:
new_img = pdb.gimp_paste_as_new()

#rotate the newly created image:
pdb.gimp_image_rotate(new_img, ...)

#export the resulting image:
pdb.gimp_file_save(new_img, ...)

#delete the loaded image and the created image:
# (as the objects being destroyed on the Python side
# do not erase then from the GIMP app, where they
# stay consuming memory)
pdb.gimp_image_delete(new_img)
pdb.gimp_image_delete(img)