我需要删除Webspeed URL中包含名称-值pairs..How的回车和换行符,可以这样做吗?有什么想法请提出来!
发布于 2013-12-03 16:25:22
要替换字符,可以使用replace函数
REPLACE function
Returns a string with specified substring replacements.
Syntax
REPLACE ( source-string , from-string , to-string ) 示例:
DEFINE VARIABLE cTxt AS CHARACTER NO-UNDO FORMAT "x(20)".
DEFINE VARIABLE cNewTxt AS CHARACTER NO-UNDO FORMAT "x(20)".
cTxt = "abc123abc123abc123".
cNewTxt = REPLACE(cTxt, "a", "-").
DISPLAY cNewTxt .您可以使用控制代码~n确定新行的目标
REPLACE(cString, "~n", "replacing character").或以个体%0d (十进制ascii代码13)和%0a's (十进制ascii代码10)为目标。
REPLACE(cString, CHR(13), "replacing character").
REPLACE(cString, CHR(10), "replacing character").发布于 2013-12-03 22:21:07
我最近需要做一些类似的事情,并发现下面的方法非常方便。这可能有点极端--它删除了所有控制代码和任何高于ascii126的代码。但是您可以很容易地调整这些限制。(我的用途是填充文本字段--所以所有这些内容对我来说都是非法输入。)
define variable hd as character no-undo initial "0123456789ABCDEF".
function hex2char returns character ( h as character ):
define variable i as integer no-undo.
if length( h ) <> 2 or index( hd, substring( h, 1, 1 )) < 0 or index( hd, substring( h, 2, 1 )) < 0 then
return "".
i = ((( index( hd, substring( h, 1, 1 )) - 1 ) * 16 ) +
index( hd, substring( h, 2, 1 )) - 1
).
if i < 32 or i >= 127 then
return "".
else
return chr( i ).
end.
function url-decode returns character ( input url as character ):
define variable xurl as character no-undo.
define variable zurl as character no-undo.
define variable pct as integer no-undo.
/* fix known trouble makers
*/
assign
xurl = replace( url, "+", " " )
xurl = replace( xurl, "%0A%0D", "~n" ) /* <LF><CR> */
xurl = replace( xurl, "%0D%0A", "~n" ) /* <CR><LF> */
xurl = replace( xurl, "%0D", "~n" ) /* <CR> */
.
pct = index( xurl, "%" ).
do while pct > 0 and xurl > "":
assign
zurl = zurl + substring( xurl, 1, pct - 1 ) + hex2char( substring( xurl, pct + 1, 2 ))
xurl = substring( xurl, pct + 3 )
pct = index( xurl, "%" )
.
end.
return zurl + xurl.
end.
display url-decode( sampleUrl ) view-as editor size 60 by 25.https://stackoverflow.com/questions/20343564
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