获取顶级域名

Question

我使用的是Url.RouteUrl("My_Route", new RouteValueDictionary(new { some = "value" }),"http","hostname")，现在我需要从url获取主机名，但只需要顶级域名。例如，我使用ui.foo.local运行我的站点，并且我需要将url路由到foo.local。在mvc或c#中有没有一种内置的方式来做这件事呢？

Answer 1

我有这个问题，并写了一个小域名Url拆分类，因为我找不到任何简单的方法来做它。我没有在上面花太多时间，所以很高兴得到一些反馈。您可以这样使用它：

var splitter = new DomainSplitter("http://stackoverflow.com");
var domain = splitter.DomainPart;

类在这里：

public  class DomainSplitter {
    public string DomainPart { get; private set; }
    public string SubDomainPart { get; private set; }
    public string SchemePart { get; private set; }
    public string QueryPart { get; private set; }

    public DomainSplitter(string url) {

        if (string.IsNullOrEmpty(url)) {
            throw new Exception("urlString or expected sub domain were null or empty");
        }

        if (url.Contains("://")) {
            ShemePart = url.Split(':')[0] + "://";
            url = url.Remove(0, FirstPart.Length);
        }


        var endOfDomainIndex = url.IndexOfAny("?/".ToCharArray());
        if (endOfDomainIndex == -1) {
            endOfDomainIndex = url.Length;
        }

        int startOfDomainIndex;
        var domainStub = url.Substring(0, endOfDomainIndex);
        var noOfDots = domainStub.Length - domainStub.Replace(".", "").Length;
        switch (noOfDots) {
            case 0:
                startOfDomainIndex = 0;
                break;

            case 1:
                startOfDomainIndex = 0;
                if (url.Contains("localhost")) {
                    startOfDomainIndex = url.IndexOf(".") + 1;
                }
                break;

            default:
                startOfDomainIndex = url.IndexOf(".") + 1;
                break;
        }

        if (url.Contains("?")) {
            QueryPart = "?" + url.Split('?')[1];    
        }
        else {
            QueryPart = "";
        }

        SubDomainPart = startOfDomainIndex > 0 ? url.Substring(0, startOfDomainIndex - 1) : "";
        DomainPart = url.Substring(startOfDomainIndex, endOfDomainIndex - startOfDomainIndex);


    }
}