首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >Oracle-Apex树超过三层

Oracle-Apex树超过三层
EN

Stack Overflow用户
提问于 2012-03-28 19:35:07
回答 1查看 581关注 0票数 0

我用下面的sql代码在APEX中生成了一棵树:

代码语言:javascript
复制
select 1 as status, 1 pid, 'Fehlermeldungen' as titel, null as icon, '1' as value, NULL as tooltip, NULL as link from dual
union
select -1 as status, 2 pid, k.kname as titel, NULL as icon, k.knr||'0' as value, NULL as tooltip, NULL as link from kunde k where 
(select count(fmtext) from fehlermeldung f where f.knr = k.knr) > 0
union
select 0 as status, 3 pid, fmtext as titel, NULL as icon, k.knr||fmnr as value, NULL as tooltip, null as link from kunde k, fehlermeldung f where f.knr = k.knr
order by value

现在,我想添加第四层,但是如果我尝试使用pid = 4创建另一个联合,则该条目将附加到最后一个select。我该如何管理它呢?

EN

回答 1

Stack Overflow用户

发布于 2012-04-04 00:17:34

首先,我尝试稍微重新格式化您的代码。看起来你所描述的应该可以正常工作。我假设你尝试过这样的东西:

代码语言:javascript
复制
select 1 as status, 1 pid, 'Fehlermeldungen' as titel, null as icon, '1' as value, 
       NULL as tooltip, NULL as link from dual
union
select -1 as status, 2 pid, k.kname as titel, NULL as icon, k.knr||'0' as value, 
       NULL as tooltip, NULL as link from kunde k 
where (select count(fmtext) from fehlermeldung f where f.knr = k.knr) > 0
union
select 0 as status, 3 pid, fmtext as titel, NULL as icon, k.knr||fmnr as value, 
       NULL as tooltip, null as link from kunde k, fehlermeldung f 
where f.knr = k.knr
-- begin my new lines...
union
select 0 as status, 4 pid, 'blank' as titel, NULL as icon, '4' as value, 
       NULL as tooltip, null as link from dual 
-- end my new lines...
order by 5

有没有可能你在错误的位置插入了额外的SELECT?向我们展示您做了什么,这样可以更轻松地进行故障排除。

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/9906658

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档