我想扩展一个已经扩展了一个类型的Fortran类型。我知道当我有一个扩展类型时,我可以写
type o1
...
type, extends(o1) :: o2
...
type(Object1) :: o1
allocate(o2::o1)当我有第三个扩展o2的类型时,这是如何工作的?这个是可能的吗?
发布于 2013-02-16 04:57:27
是。为清楚起见,重复代码并重命名:
type :: t1 ! The top level parent type.
integer :: c1 ! A component in the parent type.
end type t1
type, extends(t1) :: t2 ! An extension of t1.
integer :: c2
end type t2
type, extends(t2) :: t3 ! A further extension of t2.
integer :: c3
end type t3
! Declare an object of declared type t1.
class(t1), allocatable :: object
! Allocate that object, giving it a dynamic type of t3.
allocate(t3 :: object)
object%c1 = 1 ! c1 is a component of the declared type.
! Use select type or a type bound procedure to access c2 and c3. https://stackoverflow.com/questions/14902841
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