2个网站之间的共享会话:传统PHP和Kohana 3.1网站

Question

我有两个php网站在同一台机器。第一个站点(遗留系统)有一个基本的身份验证:检查是否设置为$_SESSION['user_id']。我在第二个站点工作(基于Kohana 3.1 )，它将扩展第一个站点的功能。这两个站点将相互链接，因此我需要在这两个系统之间共享会话。这两个站点使用相同的数据库。用户将登录第一个站点。在我的站点中，我有一个检测第一个$_SESSION['user_id']的代码，但我在保留Kohana-Auth模块的会话时遇到了问题。

第一个站点(传统站点)检查会话，如下所示：

<?php
session_start();
if(empty($_SESSION['user_id']))header("Location: index.php?action=3");
... //more dark code

这是在所有的php文件中...很多文件。

在我的Kohana站点中，我有一个控制器，它在执行任何操作之前都会检查会话。

<?php

class My_Controller extends Controller_Template {

    public function before() {
        session_start();
        $this->auth = Auth::instance();
        if ($this->auth->logged_in()) {
            //I have session in the second site... Do I have a session on the first one?

            if (!isset($_SESSION['user_id']) || $_SESSION['user_id'] == "") {
                //I have no session in the first site... I logout the user in my site
                $controller = Request::current()->controller();
                if ($controller != 'auth') {
                    Request::current()->redirect('auth/logout');
                }
            }
            $this->user = ORM::factory('user', $this->auth->get_user()->id);
        } else {
            //I have no session in the second site... Do I have a session on the first one?
            $user_id = isset($_SESSION['user_id']) ? $_SESSION['user_id'] : null;
            if (isset($user_id)) {
                $user = Model_User::get_user($user_id);
                if ($user->loaded()) {
                    //I have session in the first site... I login the user in my site
                    $this->auth->force_login($user);
                    $this->user = ORM::factory('user', $this->auth->get_user()->id);
                }
            }
            if (!$this->auth->logged_in()) {
                //I still have no session => redirect to login of the first site
                //Request::current()->redirect(...);
                echo Debug::vars("BUUUU");
            }
        }
    }

}

这段代码很容易工作:我可以从一个站点转到另一个站点，然后检测到用户……但我意识到，当用户在我的Kohana站点内的不同操作之间导航时，Users表的"logins“计数器会增加。这意味着在执行任何操作之前，"$this->auth->logged_in()“是FALSE...这意味着Auth模块不会在两次操作之间保留我的用户，而是每次都强制登录。

我不知道我能做什么。

我想从第一个站点检测会话，但我不想在每次点击时都登录这个用户。

Answer 1

我找到答案了！在Kohana3.1中，Kohana_Session类有一个默认值cookie。

/**
 * @var  string  cookie name
 */
protected $_name = 'session';

该值与PHP会话的默认名称"PHPSESSID“不匹配。

并通过在配置目录中创建名为"session.php“的配置文件来修改该值。所以我创建了一个如下的config/session.php：

<?php defined('SYSPATH') or die('No direct script access.');

return array(
    'native' => array(
        'name' => 'PHPSESSID',
    )
);

我的最后一个控制器是这样的：

<?php

class My_Controller extends Controller_Template {

    public function before() {
        $this->auth = Auth::instance();
        if ($this->auth->logged_in()) {
            //I have session in the second site... Do I have a session on the first one?

            $user_id = Session::instance()->get('user_id');

            if (!isset($user_id) || $user_id == "") {
                //I have no session in the first site... I logout the user in my site
                $controller = Request::current()->controller();
                if ($controller != 'auth') {
                    Request::current()->redirect('auth/logout');
                }
            }
            $this->user = ORM::factory('user', $this->auth->get_user()->id);
        } else {
            //I have no session in the second site... Do I have a session on the first one?

            $user_id = Session::instance()->get('user_id');

            if (isset($user_id) && $user_id != "") {
                $user = Model_User::get_user($user_id);
                if ($user->loaded()) {
                    //I have session in the first site... I login the user in my site
                    $this->auth->force_login($user);
                    $this->user = ORM::factory('user', $this->auth->get_user()->id);
                }
            }
            if (!$this->auth->logged_in()) {
                //I still have no session => redirect to login of the first site
                //Request::current()->redirect(...);
                echo Debug::vars("BUUUU");
            }
        }
    }

}

就这样..。