NSPredicate与NSArray在iphone上的竞争

Question

如何使用NSPredicate根据搜索查询过滤数组ivar中的值？我设法使用NSPredicate来对付string ivar。我有一个名为" user“的用户定义类，用于从AddressBook创建用户。以下是我的代码

  // User Defined Class named as "User"

// In User.h

@interface User : NSObject {

    NSString *firstName;
    NSString *lastName;
    NSString *company;
    UIImage *userImage;

    NSArray *phoneNumberArray;
    NSArray *emailArray;
    NSArray *urlArray;
    NSArray *addressArray;

    NSString *notes;
    NSString *dateOfBirth;
}

// In SearchViewController.m

- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText{

    //  contactsArray is NSMutableArray   
    contactsArray = [Search searchContactsWithQuery:searchText];
    NSLog(@"contactsArray count => %d",[contactsArray count]);
    [contactsTableView reloadData];
}

// In Search.m

+(NSMutableArray*)searchContactsWithQuery:(NSString*)query {

    NSLog(@"Query => %@",query);

    NSMutableArray*  predicates=[[NSMutableArray alloc] init];

    // Create all predicates
    NSPredicate * firstNamePredicate = [NSPredicate predicateWithFormat:@"firstName contains %@",query];
    [predicates addObject:firstNamePredicate];
    NSPredicate * lastNamePredicate = [NSPredicate predicateWithFormat:@"lastName contains %@",query];
    [predicates addObject:lastNamePredicate];
    NSPredicate * companyPredicate = [NSPredicate predicateWithFormat:@"company contains %@",query];
    [predicates addObject:companyPredicate];

    // Don't know how to use on array
    // === START of ARRAY Predicate ====

NSPredicate *phoneNoPredicate = [NSPredicate predicateWithFormat:@"phoneNumberArray IN %@",query];
    [predicates addObject:phoneNoPredicate];

    NSPredicate *emailPredicate = [NSPredicate predicateWithFormat:@"emailArray contains %@",query];
    [predicates addObject:emailPredicate];
    NSPredicate *urlPredicate = [NSPredicate predicateWithFormat:@"urlArray contains %@",query];
    [predicates addObject:urlPredicate];

    NSPredicate *addressPredicate = [NSPredicate predicateWithFormat:@"addressArray contains %@",query];

    // === END of ARRAY Predicate ====

    NSPredicate *notesPredicate = [NSPredicate predicateWithFormat:@"notes contains %@",query];
    [predicates addObject:notesPredicate];
    NSPredicate *dobPredicate = [NSPredicate predicateWithFormat:@"dateOfBirth contains %@",query];
    [predicates addObject:dobPredicate]; 

    // Add predicates to array
    NSPredicate *compoundPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:predicates];

    NSArray * filteredArray = [APP_DELEGATE.allUsersArray filteredArrayUsingPredicate:compoundPredicate];

    return [NSMutableArray arrayWithArray:filteredArray];

} 

使用phoneNumberArray、emailArray、urlArray和addressArray是因为用户可以具有多个条目，用于电话号码、电子邮件、地址、url，如家庭、公司、iPhone等。

如何在数组上使用谓词？任何形式的帮助都是值得感谢的。谢谢

Answer 1

您这样做是正确的，但是您需要使用字符串值创建谓词，而不是直接传递对象。

您需要使用%k而不是%@ like

[NSPredicate predicateWithFormat:@"firstName contains %k",query];

如果有帮助，请让我知道。