检测电池警告显示为iPhone

Question

有没有办法检测是否显示了电池电量警告？我向UIApplicationDidBecomeActiveNotification注册了一个通知，我想知道它是否是由于电池电量不足而触发的，这样我就可以用不同的方式处理它。

Answer 1

您可以通过编程方式监视电池电量，当电池电量达到一定水平时，您可以处理事件。

-(NSString*)batteryStateStatus:(UIDeviceBatteryState)state{
    switch ( state )
    {
        case UIDeviceBatteryStateUnknown:
            return @"Unknown";
            break;
        case UIDeviceBatteryStateUnplugged:
            return @"Unplugged";
            break;
        case UIDeviceBatteryStateCharging:
            return @"Charging";
        case UIDeviceBatteryStateFull:
            return @"Charged";
    }

    return nil;
}

-(NSString *)getBatteryPercent
{
    CFTypeRef blob = IOPSCopyPowerSourcesInfo();
    CFArrayRef sources = IOPSCopyPowerSourcesList(blob);

    CFDictionaryRef pSource = NULL;
    const void *psValue;

    NSString *thePercent;

    int i;
    int curCapacity = 0;
    int maxCapacity = 0;
    int percent;

    int numOfSources = CFArrayGetCount(sources);
    //if (numOfSources == 0) return 1;

    for (i = 0 ; i < numOfSources ; i++)
    {
        pSource = IOPSGetPowerSourceDescription(blob, CFArrayGetValueAtIndex(sources, i));
        //if (!pSource) return 2;

        psValue = (CFStringRef)CFDictionaryGetValue(pSource, CFSTR(kIOPSNameKey));

        psValue = CFDictionaryGetValue(pSource, CFSTR(kIOPSCurrentCapacityKey));
        CFNumberGetValue((CFNumberRef)psValue, kCFNumberSInt32Type, &curCapacity);

        psValue = CFDictionaryGetValue(pSource, CFSTR(kIOPSMaxCapacityKey));
        CFNumberGetValue((CFNumberRef)psValue, kCFNumberSInt32Type, &maxCapacity);

        percent = (int)((double)curCapacity/(double)maxCapacity * 100);
    }

    return [NSString stringWithFormat:@"%d",percent];
}