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社区首页 >问答首页 >安卓AudioRecord MP3编码AudioFormat.CHANNEL_IN_STEREO

安卓AudioRecord MP3编码AudioFormat.CHANNEL_IN_STEREO
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Stack Overflow用户
提问于 2013-10-14 23:15:16
回答 1查看 2K关注 0票数 0

我似乎被这个问题卡住了,

我正在尝试让https://github.com/yhirano/SimpleLameLibForAndroid在channelConfig AudioFormat.CHANNEL_IN_STEREO模式下工作。

如果我用channelConfig = AudioFormat.CHANNEL_IN_MONO而不是立体声来调用,下面的代码就能很好地工作。

我一直在玩弄

代码语言:javascript
复制
 short[] buffer = new short[mSampleRate * (16 / 8) * nChannels * 5]
 byte[] mp3buffer = new byte[(int) (7200 + buffer.length * 2 * 1.25)];

bu似乎不能让它工作。我的意思是,它的工作,但录制的声音是非常非常慢。收听这个示例https://dl.dropboxusercontent.com/u/1465252/1381762795295.mp3

Lame encoded mp3 audio slowed down - Android,似乎还有另一个类似的问题没有解决方案。

有人能帮上忙吗?

代码如下:

代码语言:javascript
复制
  new Mp3Audio(MediaRecorder.AudioSource.MIC, 44100, AudioFormat.CHANNEL_IN_STEREO, A udioFormat.ENCODING_PCM_16BIT, 128);


 public Mp3Audio(int audioSource, int sampleRate, int channelConfig, int audioFormat, int bitRate) {
    if (sampleRate <= 0) {
        throw new InvalidParameterException(
                "Invalid sample rate specified.");
    }

    mSampleRate = sampleRate;
    mBitRate = bitRate;
    if (channelConfig == AudioFormat.CHANNEL_IN_MONO) {
        nChannels = 1;
    } else {
        nChannels = 2;
    }
    builder = new Builder(mSampleRate, nChannels, mSampleRate, mBitRate);
    //builder = new Builder(44100, 1, 44100, 128);

    builder.quality(6); 

    mEncoder = builder.create();
    cAmplitude = 0;
    payloadSize = 0;
    aFormat = audioFormat;
    aSource = audioSource;
    mChannelConfig = channelConfig;


}
     public void start() {
 final int minBufferSize = AudioRecord.getMinBufferSize(mSampleRate, mChannelConfig, aFormat) * mBufferSizeFactor;      
            if (minBufferSize < 0) {
                AppHelper.Log(tag, "MSG_ERROR_GET_MIN_BUFFERSIZE");
                return;
            }
            AppHelper.Log(tag, "minBufferSize: " +      AppHelper.humanReadableByteCount(minBufferSize, true));
            aRecorder = new AudioRecord(
                    aSource, 
                    mSampleRate,
                    mChannelConfig,
                    aFormat, 
                    minBufferSize);




            short[] buffer = new short[mSampleRate * (16 / 8) * nChannels * 5]; // SampleRate[Hz] * 16bit * Mono * 5sec 
            AppHelper.Log(tag, "buffer: " + AppHelper.humanReadableByteCount(buffer.length, true));
            byte[] mp3buffer = new byte[(int) (7200 + buffer.length * 2 * 1.25)];
            AppHelper.Log(tag, "mp3buffer: " + AppHelper.humanReadableByteCount(mp3buffer.length, true));

..

EN

回答 1

Stack Overflow用户

发布于 2013-12-14 04:19:29

如果您使用两个通道(.stereo)进行记录,则需要调用lame_encode_buffer_interleaved()才能给您一个指针。

我花了几天时间才弄明白,这是你可以使用的代码:

代码语言:javascript
复制
if (lame_get_num_channels(glf) == 2)
    {
        result = lame_encode_buffer_interleaved(glf, j_buffer_l, samples/2, j_mp3buf, mp3buf_size);
    }
    else
    {
        result = lame_encode_buffer(glf, j_buffer_l, j_buffer_r, samples, j_mp3buf, mp3buf_size);
    }
票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/19363477

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