嗨,我在mysql中有这样的表:

要通过php显示这一点,如下所示:

现在,我首先获取并打印顶部的所有gradeid
$qry = "select * from grademaster";
$result= mysql_query($qry,$link);
$nro=mysql_num_rows($result);
while($row=mysql_fetch_array($result))
{
$gradeid = $row['gradeid'];
echo "<th> $gradeid </th>";
$grdid[] = $gradeid; ////////takes all grades in array
}然后从下表中获取所有详细信息,但我无法显示记录,例如在顶部,我如何显示此plz帮助
发布于 2012-08-08 20:57:52
只需复制并粘贴它,而不是你的代码,然后在浏览器中运行脚本。你会看到那张桌子。通过CSS美化它,你就完成了。
我已经在我的本地服务器上测试了它,它似乎可以工作。
$qry = "select * from grademaster";
$result = mysql_query($qry, $link);
$nro = mysql_num_rows($result);
$table = array();
$rowNum = 0;
while ($row = mysql_fetch_array($result)) {
$table[$rowNum]['ordid'] = $row['ordid'];
$table[$rowNum]['orddate'] = date('m/d/Y', strtotime($row['orddate']));
$table[$rowNum]['1001'] = intval($row['gradeid']) == 1001 ? $row['ordqty'] : '';
$table[$rowNum]['1002'] = intval($row['gradeid']) == 1002 ? $row['ordqty'] : '';
$table[$rowNum]['1003'] = intval($row['gradeid']) == 1003 ? $row['ordqty'] : '';
$table[$rowNum]['1004'] = intval($row['gradeid']) == 1004 ? $row['ordqty'] : '';
$table[$rowNum]['1005'] = intval($row['gradeid']) == 1005 ? $row['ordqty'] : '';
$rowNum++;
}
?>
<table>
<tr>
<th>ordid</th>
<th>orddate</th>
<th>1001</th>
<th>1002</th>
<th>1003</th>
<th>1004</th>
<th>1005</th>
</tr>
<?php foreach ($table as $row): ?>
<tr>
<td><?php echo $row['ordid']; ?></td>
<td><?php echo $row['orddate']; ?></td>
<td><?php echo $row['1001']; ?></td>
<td><?php echo $row['1002']; ?></td>
<td><?php echo $row['1003']; ?></td>
<td><?php echo $row['1004']; ?></td>
<td><?php echo $row['1005']; ?></td>
</tr>
<?php endforeach; ?>
</table>https://stackoverflow.com/questions/11864204
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