AsyncPlayerChatEvent，尝试查看字符串数组中的字符串是否包含在第二个字符串数组中的另一个字符串中

Question

我正在为一个运行1.6.4版本的Bukkit Minecraft服务器做一个插件。该插件被认为是为了阻止玩家发送垃圾邮件，以及审查脏话，但允许某些含有脏话的词(例如HELLo，molASSes)。我已经创建了两个字符串数组。一个包含所有脏话，第二个包含“允许”的词。

String[] curse = {"Swear1", "Swear2", "etc..."};
String[] allowed = {"Allowed1", "Allowed2", "etc..."};

我正在尝试的是，每当玩家在聊天中说话时，让插件检查消息中是否有脏话，而忽略空格和特殊字符。

这是我到目前为止所做的(抱歉，如果它有点太乱了)：

public int seconds1 = 0;
public int seconds2 = 0;
public int spam = 0;

@EventHandler
public void onPlayerChat(AsyncPlayerChatEvent event){

    Player player = event.getPlayer();
    String name = player.getName();
    seconds2 = seconds1;
    seconds1 = ((int) (System.currentTimeMillis()));

    if (seconds1 - seconds2 <= 2500){

        spam++;

        switch (spam){

        case 3: player.damage(1);
                player.sendMessage(ChatColor.GOLD + "Spam Warning: " + ChatColor.RED + "Do not spam! Spamming reduces your health.");
                break;
        case 4: player.damage(3);
                break;
        case 6: player.damage(5);
                player.sendMessage(ChatColor.GOLD + "Spam Warning: " + ChatColor.RED + "I'm warning you.");
                break;
        case 7: player.damage(6);
                break;
        case 8: player.damage(10);
                player.kickPlayer("What did I tell you about spamming?");

                for(Player p : Bukkit.getOnlinePlayers()){

                    p.sendMessage(ChatColor.BLUE + name + ChatColor.RED + " has been kicked for spamming!");

                }

                spam = 0;

                break;

        }

    }else if(seconds1 - seconds2 > 2000){

        spam = 0;

    }

    String message = event.getMessage().toLowerCase().replace("-", "").replace(" ", "").replace(",", "")
                .replace(".", "").replace("~", "").replace("!", "").replace("@", "").replace("#", "")
                .replace("$", "").replace("%", "").replace("^", "").replace("&", "").replace("*", "")
                .replace("(", "").replace(")", "").replace("_", "").replace("+", "").replace("=", "")
                .replace("{", "").replace("}", "").replace("[", "").replace("]", "").replace("|", "")
                .replace("'", "").replace("<", "").replace(">", "").replace("/", "").replace("?", "")
                .replace("`", "").replace("¸", "").replace("^", "").replace("@", "a");

    String[] curse = {"All", "Curse", "Words"};
    //I won't list the swears in this post.
    String[] allowed = {"All", "Allowed", "Words"};

    for(String blacklist : curse){

        if(message.contains(blacklist)){

            for (int i = 0; i < allowed.length; i++){

                if(allowed[i].contains(blacklist)){
                    event.setCancelled(true);
                    }else{

                    event.setCancelled(true);
                    player.chat(message.replaceAll(blacklist, "*bleep*"));
                    player.damage(5);
                    return;

                }

            }

        }

    }

}

唯一不起作用的事情是试图在允许的单词中找到脏话。我当前代码中的任何内容都不起作用。

Answer 1

我会试着使用regular expressions来做你想做的事情。试试像这样的东西

String[] swearWords = {"all", "swear", "words", "in", "here"};
// This replaces every punctuation symbol except @ by a space
String message = event.getMessage().toLowerCase().replaceAll("@", "a").replaceAll("\\p{Punct}", " ");

for(String word : swearWords){
  if(message.matches("(.* )?"+word+"( .*)?")) {
    // There has been a swear word in the message
    event.setMessage(event.getMessage().replaceAll(word, "*censored*"));
  } else {
    // The current swear word was not found in the message.
  }
}

这甚至有更高的性能;)

请注意:这是从我的手机上写的，所以请道歉格式错误和类似的:)