我使用的是Apache Tomcat7.0.39、Eclipse Java EE Juno、JavaJRE7和Java JDK 1.7.0_13。
我有一个XML的问题,一个解析错误:
Error: Invalid XML:
<?xml version="1.0" encoding="utf-8"?>
<data>
<time>9</time>
<instances>3</instances>
</data> 我的目的是从数据库中获取一些信息,并将它们放到Google Chart中。下面是我的代码:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<%@ page import="java.sql.*" %>
<%@ page import="java.sql.SQLException" %>
<%@ page import="java.sql.DriverManager" %>
<%
String idData = request.getParameter("idData");
Class.forName("com.mysql.jdbc.Driver").newInstance();
Connection conn = DriverManager.getConnection("jdbc:mysql://localhost:3306/testcd","root","");
if(conn != null)
{
Statement stmt = conn.createStatement();
stmt.execute("SELECT Id,number FROM numberInstances WHERE ID='"+ idData +"'");
ResultSet rs = stmt.getResultSet();
out.println("<?xml version=\"1.0\" encoding=\"ISO-8859-1\"?>");
out.setContentType("text/xml");
out.println("<data>");
while(rs.next())
{
out.println("<time>" + rs.getString(1) + "</time>");
out.println("<instances>" + rs.getInt(2) + "</instances>");
}
out.println("</data>");
conn.close();
}
%>有人能帮我吗?我从昨天开始就有这个问题了,我在谷歌上搜索得到的所有信息都没有帮助
如果你需要更多的信息,请问我
发布于 2013-04-18 19:42:18
最后,我将代码更改为使用文本响应而不是xml响应。获取数据的JSP代码:
Statement stmt = conn.createStatement();
stmt.execute("SELECT number FROM numberInstances WHERE ID='"+ idData +"'");
ResultSet rs = stmt.getResultSet();
while(rs.next())
{
out.println(rs.getInt(1));
}
conn.close();以及用于获取响应的JSP代码:
$.ajax({
type: "GET",
url: "resources/jsp/getInstances.jsp",
data: {idData:(cptData)},
dataType: "text",
complete: function(text)
{
instance = text.responseText*(1010);
}
});https://stackoverflow.com/questions/16079928
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