在Rails中路由使用户名成为URL：

Question

在我的Rails应用程序中，有一个设备模型-用户和一个注册表模型(每个用户都有一个注册表)。

我想改变我的路线，而不是：

"http://localhost:3000/registries/3“

它显示：

"http://localhost:3000/erinwalker“

所以我把路线改成

match '/:name' => "registries#show"

在我的控制器中执行show操作，以：

def show
@user = current_user
@user = User.find_by_name!(params[:name])
@registry = @user.registry

它可以工作，但当我现在首先创建或更新注册表时，它会显示：

Couldn't find User with name = 
app/controllers/registries_controller.rb:21:in `show'

即使表演动作起作用了？

注册表控制器: class RegistriesController < ApplicationController before_filter :authenticate_user!，:except => :show load_and_authorize_resource

# GET /registries
# GET /registries.json
def index
@registries = Registry.all
@user = current_user
respond_to do |format|
  format.html # index.html.erb
  format.json { render json: @registries }
end
end

# GET /registries/1
# GET /registries/1.json
def show
@user = current_user
@user = User.find_by_name!(params[:name])
@registry = @user.registry


respond_to do |format|
  format.html # show.html.erb
  format.json { render json: @registry }
end
end

# GET /registries/new
# GET /registries/new.json
def new
@registry = Registry.new
@user = current_user

respond_to do |format|
  format.html # new.html.erb
  format.json { render json: @registry }
end
end

# GET /registries/1/edit
def edit
@registry = Registry.find(params[:id])
@user = current_user
end

# POST /registries
# POST /registries.json
def create
@registry = current_user.build_registry(params[:registry])
@user = current_user

respond_to do |format|
  if @registry.save
    format.html { redirect_to @registry, notice: 'Registry was successfully created.' }
    format.json { render json: @registry, status: :created, location: @registry }
  else
    format.html { render action: "new" }
    format.json { render json: @registry.errors, status: :unprocessable_entity }
  end
end
end

# PUT /registries/1
# PUT /registries/1.json
def update
@registry = Registry.find(params[:id])
@user = current_user


respond_to do |format|
  if @registry.update_attributes(params[:registry])
    format.html { redirect_to @registry, notice: 'Registry was successfully updated.' }
    format.json { head :no_content }
  else
    format.html { render action: "edit" }
    format.json { render json: @registry.errors, status: :unprocessable_entity }
  end
end
end

我的所有路由：

Mystorkparty::Application.routes.draw do  

devise_for :users


resources :registries


root :to => "static_pages#home"

match '/home',    to: 'static_pages#home'

match '/:name' => "registries#show"

Answer 1

创建或更新模型时，需要发送POST /registries或PUT /registries/1。

但是/registries与您的最后一条规则match '/:name' => "registries#show"匹配，因此请求命中show操作。

如果您运行rake routes，您应该会看到如下所示：

                POST   /registries(.:format)                 registries#create
                PUT    /registries/:id(.:format)             registries#update
                DELETE /registries/:id(.:format)             registries#destroy
                       /:name(.:format)                      registries#show

您可以在您的路由中添加method参数，以便仅在GET请求时对show执行hit操作。

match '/:name' => "registries#show", :via => :get

但在未来仍有可能发生冲突。例如，如果您的注册表名称为users。因此，通常建议使用前缀(match '/r/:name')或定义一组允许的名称，或者为注册表选择安全名称。

附言:默认情况下，我不认为load_and_authorize_resource会为你的show操作工作。因为它期望params:id自动加载资源。